9514 1404 393
Answer:
5/9 m/min
Step-by-step explanation:
The depth of the water is 2/5 of the depth of the trough, so the width of the surface will be 2/5 of the width of the trough:
2/5 × 2 m = 4/5 m
Then the surface area of the water is ...
A = LW = (18 m)(4/5 m) = 14.4 m²
The rate of change of height multiplied by the area gives the rate of change of volume:
8 m³/min = (14.4 m²)(h')
h' = (8 m³/min)/(14.4 m²) = 5/9 m/min
(f o g o h)(x) = f { g [ h(x) ] }
Which means: apply first function h, then apply function g to the result, and finally apply function f to the new result.
h(25) = √25 = 5
g(5) = 5 - 3 = 2
f(2) = 3(2) = 6.
Answer: 6
Answer:
60 and 71
Step-by-step explanation:
Take 131
subtract the 11 from the question to get 120
Then split 120 into two parts - 60.
Add the 11 to one part
That's it! ^^
