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4 years ago

a quadrilateral has perpendicular diagonals.is this enough to determine what type of quadrilateral it is?

Mathematics

1 answer:

kenny6666 [7]4 years ago

3 0

No - it could be a rhombus or a square

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The sum of fifteen and six times a number t is eighty-one. What is the number?

kari74 [83]

Equation: 15 + 6t = 81
Work: 15 + 6t = 81
-15 -15

6t = 66
t = 11

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3 years ago

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A company runs food service concessions for sporting events throughout the country. Their marketing research department chose a

MA_775_DIABLO [31]

Answer:

Step-by-step explanation:

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3 years ago

15 point help asap marking brainlest!!!!!!!!!!!!!!

ziro4ka [17]

slope =(y2-y1)/(x2-x1)

m=(-1-5)/(1--1)

m=-6/2

m=-3

y-y1=m(x-x1) point slope form

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3 years ago

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The elevation at the top of Mount Everest is 8850 meters. The temperature falls at a rate of 1 degree C per 100 meters. The base

Oksi-84 [34.3K]

5400 = -3 8850-5100=3750m 1c = 100m
5300 = -2 3750/100 =37.5
5200 = -1
5100 = 0

answer = 37.5 degrees C

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4 years ago

Let f(x) = x² + x - 6 and g(x) = 3x - 6, what are f ⋅ g and f/g. state the resulting function and it's domain.

Lady bird [3.3K]

Answer:

$f \cdot \: g = 3 {x}^{3} - 3 {x}^{2} - 24x + 36$

Domain: All real numbers

$\frac{f}{g} = \frac{x + 3}{3}$

Domain: x≠2

Step-by-step explanation:

The given functions are

$f(x) = {x}^{2} + x - 6$

and

$g(x) = 3x - 6$

$f \cdot \: g = f(x) \cdot \: g(x)$

This implies that:

$f \cdot \: g = (3x - 6)( {x}^{2} + x - 6)$

We expand to get:

$f \cdot \: g = 3x ( {x}^{2} + x - 6) - 6( {x}^{2} + x - 6)$

We expand to get:

$f \cdot \: g = 3 {x}^{3} + 3 {x}^{2} - 18x - 6{x}^{2} - 6 x + 36$

We group like terms to get:

$f \cdot \: g = 3 {x}^{3} - 3 {x}^{2} - 24x + 36$

This is a polynomial function, the domain is all real.

Also;

$\frac{f}{g} = \frac{f(x)}{g(x)}$

$\frac{f}{g} = \frac{ {x}^{2} + x - 6 }{3x - 6}$

Factor to get:

$\frac{f}{g} = \frac{(x - 2)(x + 3)}{3(x - 2)}$

Cancel common factors:

$\frac{f}{g} = \frac{x + 3}{3}$

The domain is all real numbers, except numbers that will make the denominator zero.

$x \ne2$

4 0

4 years ago