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3 years ago

Please Help!!!

Mathematics

2 answers:

meriva3 years ago

8 0

3.9 - 0.234 = 3.666

Hope it helped

Simora [160]3 years ago

7 0

1st:You multiply 3.9*.6=2.34
2nd:You subtract 3.9-2.34=1.5
The answer is 1.5

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A car salesman receives a base weekly salary of $150 plus a commission of $325 per car sold. What is the equation that models th

Temka [501]

Given :

Weekly salary , S = $150.

Commission per car , C = $325.

To Find :

The the equation that models the weekly salary of a car salesman.

Solution :

We know it is a quadratic equation :

Let , the equation is , y = mx + c

Here, x is number of car sold in a week.

For x = 0 ( He will not get commission)

So , Salary is $150 = c .

For x = 1

Salary is $( 150 + 325 ) = $475 = m(1) + c

Therefore , m = $325 and c = $150.

Required linear equation is y = 325x + 150.

Hence, this is the required solution.

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Step-by-step explanation:

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3 years ago

Two datasets arranged in descending order are: {8, x, 4,1) and (9. y, 5,2). If the medians of

OverLord2011 [107]

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Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Please help me out :P

Veseljchak [2.6K]

cos θ = $\frac{-4\sqrt{65} }{65}$ , sin θ = $\frac{-7\sqrt{65} }{65}$ , cot θ = 4/7, sec θ = $\frac{-\sqrt{65} }{4}$ , cosec θ = $\frac{-\sqrt{65} }{7}$

<h3>What are trigonometric ratios?</h3>

Trigonometric Ratios are values of all the trigonometric functions based on the value of the ratio of sides in a right-angled triangle.

Sin θ: Opposite Side to θ/Hypotenuse

Tan θ: Opposite Side/Adjacent Side & Sin θ/Cos

Cos θ: Adjacent Side to θ/Hypotenuse

Sec θ: Hypotenuse/Adjacent Side & 1/cos θ

Analysis:

tan θ = opposite/adjacent = 7/4

opposite = 7, adjacent = 4.

we now look for the hypotenuse of the right angled triangle

hypotenuse = $\sqrt{7^{2} + 4^{2} }$ = $\sqrt{49+16}$ = $\sqrt{65}$

sin θ = opposite/ hyp = $\frac{7}{\sqrt{65} }$

Rationalize, $\frac{7}{\sqrt{65} }$ x $\frac{\sqrt{65} }{\sqrt{65} }$ = $\frac{7\sqrt{65} }{65}$

But θ is in the third quadrant(180 - 270) and in the third quadrant only tan and cot are positive others are negative.

Therefore, sin θ = - $\frac{7\sqrt{65} }{65}$

cos θ = adj/hyp = $\frac{4}{\sqrt{65} }$

By rationalizing and knowing that cos θ is negative, cos θ = - $\frac{-4\sqrt{65} }{65}$

cot θ = 1/tan θ = 1/7/4 = 4/7

sec θ = 1/cos θ = 1/ $\frac{4}{\sqrt{65} }$ = - $\frac{-\sqrt{65} }{4}$

cosec θ = 1/sin θ = 1/ $\frac{\sqrt{65} }{7}$ = $\frac{-\sqrt{65} }{7}$

Learn more about trigonometric ratios: brainly.com/question/24349828

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