Question

What are the solutions to the equation 2(x+1)^2=32

Answer 1

Answer:

Simplify 2(x+1)\times 22(x+1)×2 to 4(x+1)4(x+1).

4(x+1)=324(x+1)=32

2 Divide both sides by 44.

x+1=\frac{32}{4}x+1=

4

32

3 Simplify \frac{32}{4}

4

32

to 88.

x+1=8x+1=8

4 Subtract 11 from both sides.

x=8-1x=8−1