
In case there is no double entry system is followed, profit can be calculated by comparing the opening and closing capital. In the given situation this can be calculated as:
Opening Capital Rs.200000
Add: Capital Introduced Rs.200000
Add: Profit for the year Rs. 250000
Less: Loss for the year Rs.NIL
Less: Drawings Rs. 30000
--------------------
Capital at the end of the year Rs.620000
-------------------
Loan taken is a liability and loan given is asset, that will not affect the capital.
<h2>ƑƠԼԼƠƜ MЄ❤</h2>
Answer:
C(t)=5000 -10t
Step-by-step explanation:
There are many examples in the real world of relationships that are functions.
For example, imagine a tank full of water with a capacity of 5000 liters, this tank has a small hole, by which 10 liters of water are lost every hour.
If we call C the amount of water in the tank as a function of time, then we can write the following equation for C:

Where:
C (t): Amount of water in the tank as a function of time
: Initial amount of water in the tank at time t = 0
a: amount of water lost per hour
t: time in hours
Then the equation is:
The graph of C (t) is a line of negative slope. This relation is a function since for each value of t there is a single value of C.
Its domain is the set of all positive real numbers t between [0,500]
Because the time count starts at t = 0 when the tank is full and ends at t = 500 when empty
Its Range is the set of all positive real numbers C between [0,5000] Because the amount of water in the tank can never be less than zero or greater than 5000Litres
Answer:
the ramp must be lowered
Step-by-step explanation:
Use the definition of the sine function to find the height of a ramp that is 8°.
Sine = Opposite/Hypotenuse
sin(8°) = height/8
height = 8×sin(8°) = 1.11
The height Nate's dad allows is 1.11 feet. At 1.5 feet, the ramp is too high.
The ramp must be lowered.
Answer:
the ratio less than 15/24 can be 1:2, 7:8
Based on the information of the table, you have:
1. The ratio is 105/150. By simplifying you get for the ratio 7/10.
2. The students that prefer action movies are 75+90 = 165 and the total numbe of students is 180+240 = 420. Then, the fraction of students who prefer action movies is:
165/420 = 11/28
3. The fraction of seventh graders students that prefer action movies is:
75/180 = 5/12
4. The percent of student that prefer comedy is:
105 + 150 = 255 total student that prefer comedy
420 total number of students
the fraction is:
(x/100)420 = 255
solve for x:
x = 255(100/420)
x = 60.71
the percent of students is 60.71%
5. The percent of eighth graders student who prefer action moveis is:
(x/100)240 = 90
x = 90(100/240)
x = 37.5
the percent of students is 37.5%
6. To determine which from the given grades has the greatest percent of student that prefer action movies, calculate the percent of student in seventh-grade:
(x/100)180 = 75
x = 75(100/180)
x = 41.66
the percent of student is 41.66%
then, seventh grade has the greatest percent of student that prefer action movies.