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jeyben [28]
3 years ago
5

Calculate the distance between (4,6) (5,0)

Mathematics
1 answer:
kramer3 years ago
5 0

The distance between two (4, 6) and (5, 0) is 6.08 units.

Solution:

The given points are (4, 6) and (5, 0).

x_1=4, y_1=6, x_2=5, y_2=0

<u>To find the distance between two points:</u>

Distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(5-4)^2+(0-6)^2}

d=\sqrt{1^2+(-6)^2}

The value of 1² = 1

The value of (–6)² = 36

d=\sqrt{1+36}

d=\sqrt{37}

d = 6.08

The distance between two (4, 6) and (5, 0) is 6.08 units.

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Gary needs to solve 120 problems by a certain day. He calculated, that to finish all the problems in time, he needs to solve 5 p
kozerog [31]

Answer:

To be done in time, he would need to solve 6 questions per day on the days that he is not on trip

Step-by-step explanation:

If he solves the problems 5 per day, the total number of days that would be required to finish solving the problem would be 120/5 = 24 days

Now, he has 4 free days which would be for a family trip. The number of questions that he would miss during those trip days will be 4 * 5 = 20 questions

Now since he wants to still finish on time, what is needed to be done is to share the 20 left overs amongst the 20 days which he has to work

This makes a total of 1 question per day

Adding this to the 5 questions per day he has before will be = 6 questions per day

7 0
3 years ago
What are the x and y-intercepts of the line described by the equation?<br> -6x + 3y = 18.9
-BARSIC- [3]

Answer:

x-intercept - x = 1/2y - 3.15

y-intercept - y = 2x + 6.3

Step-by-step explanation:

For x,

-6x + 3y = 18.9

-6x = -3y + 18.9

x = -3y/-6 + 18.9/-6

x = 1/2y - 3.15

For y,

-6x + 3y = 18.9

3y = 6x + 18.9

y = 6x/3 + 18.9/3

y = 2x + 6.3

8 0
3 years ago
Please help Explanation will be appreciated thanks,
Genrish500 [490]

Answer: A; 6.3%

Step-by-step explanation:

Problem 1

For the first problem, we first want to find y so that we can plug it into the expression.

We can use elimination method for the system of equations to solve.

3x+3y=21

3x-y=5

We subtract both equations to eliminate x.

4y=16                                        [divide both sides by 4]

y=4

Now that we know y, we can plug it into the expression.

\frac{4}{2} -3                                         [divide]

2-3                                         [subtract]

-1

We know that the answer is A.

--------------------------------------------------------------------------------------------------------

Problem 2

For the second problem, we need to know how to calculate percent error. The formula for precent error is \frac{|measured-exact|}{exact} *100%. We know that the exact value is 80 because the buyer was supposed to given 80. 75 is the measured value because that was what the buyer was given.

\frac{|75-80|}{80} *100%                               [subtract]

\frac{|-5|}{80} *100%                                   [solve absolue value]

\frac{5}{80} *100%                                     [divide]

0.0625*100%                               [multiply]

6.25

Since the problem said to round to one decimal place, we know that the answer is 6.3%.

4 0
3 years ago
I need help on this one I have the image attached
mart [117]

Answer:

x = 40

Step-by-step explanation:

The ADF is 90 degrees so the CAF will also be 90

So you do

( x + 15 ) + 90 + 35 = 180

x + 15 + 90 + 35 - 90 = 180 -90

x + 15 + 35 = 90

x + 15 + 35 - 35 = 90 - 35

x + 15 = 55

x + 15 - 15 = 55 - 15

x = 40

4 0
3 years ago
Help me now plsss! can't think this one out.
ra1l [238]
She worked 30 hours per week.

The problem turns out to be the following:
2x+15=3x-15.
First you need to have only one x variable so you subtract the X's:
3x-2x=X
The problem now turns into 15=x-15.
You have to isolate the X so you do x+15. You have to do the same to the other side so 15+15=30, therefore x=30
8 0
3 years ago
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