Continuous compounding is the mathematical limit that compound interest can reach.
It is the limit of the function A(1 + 1/n) ^ n as n approaches infinity. IN theory interest is added to the initial amount A every infinitesimally small instant.
The limit of (1 + 1/n)^n is the number e ( = 2.718281828 to 9 dec places).
Say we invest $1000 at daily compounding at yearly interest of 2 %. After 1 year the $1000 will increase to:-
1000 ( 1 + 0.02/365)^365 = $1020.20
with continuous compounding this will be
1000 * e^1 = $2718.28
Answer:
ok we start form thedrgvbjm,;.Step-by-step explanation:
The solution for that proplem is X=4,1
Using it's concept, it is found that the range of the function is given as follows:
.
<h3>What is the range of a function?</h3>
The range of a function is the set that contains all possible output values for the function. In a graph, the range is the set that contains the values of y.
In this graph, the extremes are at y = 0 and y = 7, and the diagonal line crosses as values in this interval, as shown in the graph at the end of the answer, hence the range of the function is given as follows:
.
More can be learned about the range of a function at brainly.com/question/24374080
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1. There
are 10, 000 combinations, you have 10 choices for the four digit and there are
10 x 10 x 10 x 10 which is 4-digit combination from 1-9. This is called combinations;
the calculation comes out to 10^4.