Formatting is kind of messed up. I'm assuming the differential equations is dy/dx = 6x
You need to get all the x's on one side and y'all on the other.
dy =6x dx
Integrate both sides.
y = 3x^2 + C
Now plug in the given values
y(0) = 4 = 3(0)^2 + C
C = 0
y = 3x^2
Plug 1 in for x to find the value of y(1)
y(1) = 3(1)^2 = 3
Answer:
Yeah
Step-by-step explanation:
The picture is cut off. We can't solve :/
