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Zanzabum
3 years ago
13

What are the solutions to the systems? y=x^2-4x-2 y=x-2

Mathematics
1 answer:
kirill115 [55]3 years ago
6 0
<span>y=x^2-4x-2
y=x-2

x^2-4x-2=x-2\\\\x^2-4x-2-x+2=0\\\\x^2-5x=0\\\\x(x-5)=0\\\\x=0 \ or \  x-5=0

x=0 or x=5 

y = x - 2
1)
x=0
y = 0 - 2= -2
2)
x=5
y=5-2=3

Answer
x=0 , y=-2
or
x=5 , y=3</span>
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Answer:

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Step-by-step explanation:

Given

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= - 3x² + 8xy + 3y² ← factor out - 1 from each term

= - 1(3x² - 8xy - 3y²) ← factor the quadratic

Consider the factors of the product of the coefficient of the x² term and the coefficient of the y² term which sum to give the coefficient of the xy- term.

product = 3 × - 3 = - 9 and sum = - 8

The factors are - 9 and + 1

Use these factors to split the xy- term

3x² - 9xy + xy - 3y² ( factor the first/second and third/fourth terms )

= 3x(x - 3y) + y(x - 3y) ← factor out (x - 3y) from each term

= (x - 3y)(3x + y)

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(x + 2y)² - (2x - y)² = - (x - 3y)(3x + y)

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Step-by-step explanation:

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Answer:

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