3 years ago

What are the solutions to the systems? y=x^2-4x-2 y=x-2

1 answer:

6 0

<span>y=x^2-4x-2
y=x-2

$x^2-4x-2=x-2\\\\x^2-4x-2-x+2=0\\\\x^2-5x=0\\\\x(x-5)=0\\\\x=0 \ or \ x-5=0$

x=0 or x=5

y = x - 2
1)
x=0
y = 0 - 2= -2
2)
x=5
y=5-2=3

Answer
x=0 , y=-2
or
x=5 , y=3</span>

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