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zlopas [31]
2 years ago
7

Need help?????????!!!!!!!

Mathematics
1 answer:
julsineya [31]2 years ago
3 0

Answer:

73 and -23 hope this helped hon :)

Step-by-step explanation:

y=-8x+9

plug in -8

y=-8(-8)+9

y=64+9

y=73

y=-8x+9

plug in 4

y=-8(4)+9

y=-32+9

y=-23

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we know by definition that

f^{-1}(f(x))=x\\\\f^{-1}(\frac{2x}{3})=x\\\\f^{-1}(x)=ax\\\\f^{-1}(\frac{2x}{3})=a(\frac{2x}{3})=x\\\\f^{-1}(x)=\frac{3x}{2}

so now we evaluate

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and if we want to do an extra step

f^{-1}(f(6))=6\\\\f^{-1}(\frac{2*6}{3})=f^{-1}(4)=\frac{3*4}{2}=6

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