The answer to Part A is :
D. w ≥ 6 inches
The answer to Part B is :
C. w ≥ 9 inches
To find how many times in one second the Ruby Throated Hummingbird beats his wings per second you would need to divide the 3 by 3 to get 1 second.
Then you would also divide the 159 by 3 to get <u>53</u>, which is the answer.
Answer:
<u>the mean-average of the data without the outliers is 22572/94 = 240.12766 correct to four digits.</u>
Step-by-step explanation:
If the six outliers are removed, what is the mean average of the remaining data... is ASSUMED what the question was supposed to ask. I'll go out on a limb here, because there really isn't much else you can calculate with just
this much data anyways. I refer to the mean or average as the mean-average....just sayin'
Mean-Average = total/count , which means the total = count * mean-average.
Well, the data containing the outliers has a mean-average of 267 and a count of 100 statistics as given in the problem. So the total of all of the data including the outliers is 26700.
Likewise, the six outliers have a mean-average of 688 as given in the problem.
So the total of the outliers is 688 * 6 = 4128.
As a result, the total of the 94 statistics when the six outliers are rejected is 26700-4128=22572.
Answer: 1.08T and (1+8/100)T
Step-by-step explanation:
Given: The average temperature two Sundays ago was T degrees Celsius.
Since, last Sunday, the average temperature was 8% higher than the average temperature two Sundays ago.
⇒ The average temperature last Sunday
Since 8%=0.08
Therefore, The average temperature last Sunday
⇒ The average temperature last Sunday
⇒ The average temperature last Sunday
⇒ The average temperature last Sunday
Thus, the right option is 1.08T and (1+8/100)T
