What is the area of the composite shape

Mathematics

1 answer:

svlad2 [7]2 years ago

4 0

First, let’s find the area of the larger square. We know that the smaller square extend out 2ft and is2ft up. Well take these measures, and subtract the 2ft from the 12 ft at the top, and get 10ft, then add the 2ft to the left side, and find that it’s 6ft. We have these measures: 6ft 6ft 10ft 10ft for the larger rectangle. Let’s find the area. The are formula for a rectangle is Base(10ft) times height(6ft) . Thus 60ftsqrd. Next, let’s do the smaller rectangle. We do the same formula, 4 times 2, and get 8ftsqrd, add them together: 60ft + 8ft = 68ft!

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saw5 [17]

Answer:

Step-by-step explanation:

When looking at the number line, we can see the distance between A and B is one unit

A |-2| + |-1| = 2+1 =3 That is not 1 unit

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3 years ago

The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c

valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

Step-by-step explanation:

The area of a rectangle with length $L$ and width $W$ is $A= L\cdot W$ so the differential of <em>A</em> is

$dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W$

$\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L$ so

$dA=W\Delta L+L \Delta W$

We know that each error is at most 0.1 cm, we have $|\Delta L|\leq 0.1$ , $|\Delta W|\leq 0.1$ . To find the maximum error in the calculated area of the rectangle we take $\Delta L = 0.1$ , $\Delta W = 0.1$ and $L=55$ , $W=49$ . This gives