2 years ago

One number exceeds another by 18 and their sum is 36.

Mathematics

1 answer:

AnnZ [28]2 years ago

3 0

x - first number

x + 18 - second number

x + (x + 18) = 36

x + x + 18 = 36

2x + 18 = 36 | - 18

2x = 18 | : 2

x = 9

First number: x = 9

Second number: x + 18 = 9 + 18 = 27

Those numbers are 9 and 27.

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