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Mars2501 [29]
3 years ago
9

A line contains the points (-4,1) and (4,6). Decide whether or not each point of these points is also on the line.

Mathematics
2 answers:
V125BC [204]3 years ago
4 0

Answer:

its a

Step-by-step explanation:

hsysnudfgbsdtyfvthv

WINSTONCH [101]3 years ago
3 0

Answer:

Step-by-step explanation:

hubububhbhub

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Determine the amounts of 20% and 50% salt solutions that should be mixed to obtain 300 gallons of 41% salt solution.
tresset_1 [31]
Assume that solution with 20% and 50% salt is x and y gallons respectively.

Therefore,

x+y = 300 => y=300-x

Additionally
20x+50y = 300*41 = 12300

Substituting for y

20x+50(300-x) = 12300 => 20x+15000-50x = 123000 => -30x = -2700

x= 90 gallons
y= 300-x = 300 - 90 =210 gallons

3 0
3 years ago
Subtract 5x^2-8x-1 from <br> -(5x^2 -x - 8).
Jobisdone [24]

Answer:

-10x² - 7x + 7

Step-by-step explanation:

Subtract:

  • -5x² - 8x - 1 - (5x² - x - 8)
  • -5x² - 5x² - 8x + x - 1 + 8
  • -10x² - 7x + 7

Remember: subtracting a negative number is adding that number

-Chetan K

3 0
2 years ago
Read 2 more answers
Plz help i will give branlyist to first right answer
RideAnS [48]
P = (2.5,0)
T=(-1.5,-1)
Point R is located (1.5 -2.5)
5 0
2 years ago
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Is the function y=<br> -<br> 9x–6 linear
alina1380 [7]

Answer:

yes

Step-by-step explanation:

5 0
3 years ago
A closed cylindrical can of fixed volume V has radius r.a) Find the surface area, S, as a function of r.b) What happens to the v
andrey2020 [161]

Answer:

Step-by-step explanation:

This question is incomplete; here is the complete question.

A closed cylindrical can of fixed volume V has radius r. (a) Find the surface area, S, as a function of r. (b) What happens to the value of S approaches to infinity? (c) Sketch a graph of S against r, if  V=10 cm³.

A closed cylindrical can of volume V is having radius r and height h.

a). Surface area of a cylinder is given by

S = 2(Area of the circular sides) + Lateral area of the can

S = 2πr² + 2πrh

S = 2πr(r + h)

b). Since surface area is directly proportional to radius of the can

S ∝ r

Therefore, when r approaches to infinity (r → ∞)

c). If V = 10 cm³ Then we have to graph S against r.

From the formula V = πr²h

10 = πr²h

h = \frac{10}{\pi r^{2}}

By placing the value of h in the formula of surface area,

S = 2\pi r(r+\frac{10}{\pi r^{2}})

Now we can get the points to plot the graph,

r       -2             -1         0       1            2

S    -13.72     -13.72     0    26.28    35.13

7 0
3 years ago
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