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3 years ago

9

Estimate the product 8.91 × 34,871.081

1 answer:

aleksklad [387]3 years ago

3 0

The way I would do it is by rounding 8.91 up to 9 and I would round 34,871.081 up to 35,000.
9*35,000=315,000

Hopefully I was able to help in some way.

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marishachu [46]

The answer is $6.60

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What are the apparent coordinates of the midpoint of diagonal ac

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4 years ago

Consider the following hypothesis test:

Scrat [10]

Answer:

$z=\frac{27.4-26}{\frac{6}{\sqrt{40}}}=1.48$

The p value can be founded with the following probability:

$p_v =P(z>1.476)=0.0694$

Step-by-step explanation:

Information given

$\bar X=27.4$ represent the sample mean

$\sigma=6$ represent the population deviation

$n=40$ sample size

$\mu_o =26$ represent the value to verify

z would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to check if the true mean for this case is higher than 26, the system of hypothesis would be:

Null hypothesis: $\mu \leq 26$

Alternative hypothesis: $\mu > 26$

The statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

Replacing the info we got:

$z=\frac{27.4-26}{\frac{6}{\sqrt{40}}}=1.48$

The p value can be founded with the following probability:

$p_v =P(z>1.476)=0.0694$

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3 years ago

A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is ___ units. The point

mixas84 [53]

Answer:

The radius is 5 units

(-7,-1) and (-7,5) lies on the circle

Step-by-step explanation:

Use the distance formula to find the distance between the center and the given point that gives you the radius.

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The center is (-3,2) and the point on the circumference is (1,5)

$r=\sqrt{(1--3)^2+(5-2)^2}$

$r=\sqrt{(4)^2+(3)^2}$

$r=\sqrt{16+9}$

$r=\sqrt{25}$

$\therefore r=5$

The radius is 5 units.

The equation of the circle is given by:

$(x--3)^2+(y-2)^2=5^2$

$(x+3)^2+(y-2)^2=25$

When x=-7, we obtain y by substituting into the equation of the circle:

$(-7+3)^2+(y-2)^2=25$

$(-4)^2+(y-2)^2=25$

$16+(y-2)^2=25$

$(y-2)^2=25-16$

$(y-2)^2=9$

$y-2=\pm \sqrt{9}$

$y=2\pm 3$

$y=-1$ or y=5

Therefore (-7,-1) and (-7,5) lies on the circle.

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4 years ago

Which number lies between √5 and √6?

zhannawk [14.2K]

Lets inaugurate the roots

$\\ \bull\leadsto \sqrt{5}=2.24$

$\\ \bull\leadsto \sqrt{6}=2.448$

Now coming to options

$\overline{2.3}\checkmark$
π=3.141
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3 years ago

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