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Finger [1]
3 years ago
8

Write 15 1/20 as a improper fraction and as a decimal then tell wether the decimal is terminating or repeating

Mathematics
2 answers:
kirill115 [55]3 years ago
6 0
Note, * means multiply

15 and 1/20=15+1/20=(15*20)/20+1/20=300/20+1/20=201/20 is the improper fraction

15 and 1/20=15 and 5/100=15+0.05=15.05
kherson [118]3 years ago
5 0

idk i'm terrible with math sorry


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Park two has 12 more benches than Park one. If 2 benches were transferred from Park two to Park one, then Park two would have 2
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Answer:

There were 6 benches in park 1 and 18 benches in park 2.

Step-by-step explanation:

Let x be the no of benches in Park 1 and y in park 2.

Given that there are 12 more benches in park 2 than 1

Writing this in equation form, we have y = x+12 ... i

Next is if 2 benches were transferred from park 2 to park 1, then we have

x+2 in park 1 and y-2 in park 2.

Given that y-2 = twice that of x+2

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Rewrite by adding 2 to both sides of equation ii.

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18 = 6+12 hence I condition is satisfied

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Which is a correct two column proof. Given <4 and
vladimir1956 [14]

The initial statement is:    QS = SU   (1)

                                    QR = TU    (2)

 

We have to probe that:  RS = ST

 

 

Take the expression (1):                     QS       =   SU

We multiply both sides by R                (QS)R   =   (SU)R

 

 

But    (QS)R = S(QR)     Then:            S(QR)   =   (SU)R     (3)

 

From the expression (2):  QR = TU. Then, substituting it in to expression (3):

 

                                                       S(TU)   =   (SU)R     (4)

 

But  S(TU) = (ST)U  and (SU)R = (RS)U

 

Then, the expression (4) can be re-written as:

 

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Eliminating U from both sides you have:     (ST) = (RS)    The proof is done.

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⊹˚ʚ ❑Answer︰3+(10n)

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