Answer:
1/2x<=y
Step-by-step explanation:
you find the equation first
Answer:
the coefficient of the 2nd term: - 38
Step-by-step explanation:
V = 2x (4x + 1) (5x - 6)
=(8x² + 2x) (5x - 6)
= 40x³ - <u>38</u> x² - 12x
<u><em>Answer:</em></u>
Density of jam = 11.35 kg/m³
<u><em>Explanation:</em></u>
<u>1- Getting the mass of the jam:</u>
<u>We are given that:</u>
Jam is put in 6 jars
the weight of one empty jar = 200 grams
<u>Therefore: </u>
weight of 6 empty jars = 6 * 200 = 1200 grams
<u>We are also given that:</u>
Weight of all jars filled with jam is 5400 grams
<u>Therefore:</u>
mass of jam = total mass of jam and jars - mass of 6 empty jars
mass of jam = 5400 - 1200
mass of jam = 4200 grams
<u>2- Getting the volume of the jam:</u>
We are given that the 6 jars had a total volume of 0.37 m³ and that they were completely filled with jam
<u>This means that:</u>
Volume of jam = 0.37 m³
<u>3- Getting the density of jam:</u>
<u>Density can be calculated using the following rule:</u>
![Density = \frac{mass}{volume}](https://tex.z-dn.net/?f=Density%20%3D%20%5Cfrac%7Bmass%7D%7Bvolume%7D)
<u>We have:</u>
Mass of jam = 4200 grams = 4.2 Kg
Volume of jam = 0.37 m³
<u>Therefore:</u>
![Density = \frac{4.2}{0.37} = 11.35 kg/m^3](https://tex.z-dn.net/?f=Density%20%3D%20%5Cfrac%7B4.2%7D%7B0.37%7D%20%3D%2011.35%20kg%2Fm%5E3)
Hope this helps :)
The solutions are basically the points on the graph that the line passes through. The best way to pick them is to use the whole numbers that are on the corners of the little boxes instead of the middle.
(4, -5)
(3, -3)
(1, 1)
(0, 3)
(-1, 5)
and so on.