Answer: m = 10
.........................
<span>At a corner gas station, the revenue R varies directly with the number g of gallons of gasoline sold. If the revenue is $44.50 when the number of gallons sold is 10, find a linear equation that relates revenue R to the number g of gallons of gasoline. Then find the revenue R when the number of gallons of gasoline sold is 15.5.
Solution:
As the question mentioned the direct relationship between the quantities, hence
10 gallons of gasoline sold = $44.50
15.5 gallons of gasoline sold = $x
by cross multiplication, we get that
10x = 15.5 * 44.50
which implies that
x = 68.975
Thus by $</span>68.975 revenue is obtained by selling 15.5 gallons of gasoline.
<span>For every car
Mike earns------------------ >$200 plus 3% commission</span>
3 cars-----------------
> $200*3+$32,343*0.03=600+970.29=$1570.29
Total earnings
for a week is $1570.29
A=p(1+r/100)^n
A=2500(1+4/400)^16
A=2931.45
This is a unit multiplier of sorts
1,900,000 x 45/30
Simplify
1,900,000 x 3/2
2,850,000
