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3 years ago

6

A wheel whose radius is 50 centimeters completes 6 radians in 1 seconds. What is the linear speed of a point on the rim of the w

heel? Convert your answer to meters per second (m/s).

1 answer:

Triss [41]3 years ago

4 0

Answer:

3m/seconds

Step-by-step explanation:

In this problem we are required to solve for linear speed of the rotating wheel

The linear speed =angular speed x raduis

Given data

Radius r= 50cm

Converting from cm to m

50/100= 0.5m

Angular velocity w= 6rad/s

V=wr

V= 6*0.5m

V=3m/s

The linear speed is 3m/seconds

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What is the domain of f(x) = √x – 4 over the set of real numbers?

nikklg [1K]

Answer:

<u>(2) x </u> $\geq \\$ <u> 4</u>

Step-by-step explanation:

Given the sqrt(x), x $\geq \\$ zero

So, given sqrt(x -4), x -4 $\geq \\$ 0

Now solve for x

x - 4 $\geq \\$ 0

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2 years ago

HELPPP!!!! Both questions are incredibly confusing to me !!!!!

Darya [45]

Answer:

Step-by-step explanation:

I'm going to start with problem 3. You need to become familar with the kind of tricks teachers play on you.

Problem 3 depends on getting RS = RW.

RT = RT Reflexive property

<STR = <WTR A straight line having 1 rt angle actually has 2

ST = TU They are marked as equal

Triangle STR=Triangle WTR SAS

RS = RW Corresponding parts of = triangles are =

8x = 6x + 5 Subtract 6x from both sides

8x -6x = 6x - 6x + 5 Combine

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RU = 6*2.5 + 5

RU = 15 + 5

RU = 20

Now we can play with Question 4.

This question depends on the method used in three, although not entirely.

What you need to know is that W is on RT when you take a ruler and make RT longer. You can put W anywhere as long as it is on RT when it is made longer.

Directions

Make RT longer. Draw down and to your right.

Put a point anywhere on the length starting at T. Label this new point as W. There's your W. It goes anywhere on the part of RT made longer.

Draw UW.

Label UW as 8

Now draw another line from S to W. Guess what? By the methods used in question 3, it's also 8. So SW = 8

TW = TW Reflexive

<UTW = STW Same reason as in 3. UtW is a right angle

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7 0

3 years ago

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ycow [4]

Answer:

should be 30

Step-by-step explanation:

triangles have 180°

if x is 30

2x is 60

the other angle is 90

add those all together and you get 180°

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3 years ago

Verify by substitution whetherthe given functions are solutions of the given DE. Primes denote derivatives with respect to x.y!!

julia-pushkina [17]

Complete Question

The complete question is shown on the first uploaded

Answer:

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Step-by-step explanation:

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Let consider the first equation to substitute

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So

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So

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This means that $y_2$ is not a solution of the differential equation

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$y_3 = sin 2x$

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So

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So

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3 years ago

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umka2103 [35]

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x

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3 years ago