Question

Assume that the cheetah travels an average of 40 mph to go from its resting place to a rock

Answer 1

Here is a hopefilly more simple answer:

a. Set up the table as follows. Label the rows "To the River" and "From the River." Label the  columns "Distance," "Rate," and "Time (in Hours)." Let t represent the unknown quantity  in the problem. Fill in the table.

Answer:

                            distance         rate            time

to the river         40(0.25-t)    40 mph       0.25-t

from the river          70t          70 mph            t

b. From the table, set up an equation relating the distances.

Answer:

40(0.25-t)=70t

C. Solve the problem. Write the answer in a complete sentence, stating it in terms of  minutes and seconds.

Answer:

40(0.25-t)=70t  → solve for this equation

10-40t=70t

10=110t

t=10/110=1/11 hour

↓

1/11 hour = (1/11)*60 minutes = 60/11 minutes = 5 5/11 minutes

road to the river → 5 minutes 27 seconds

road from the river → 9 minutes 33 seconds

hope this helped :)

Answer 2

Answer:

The road from the river takes nearly 5 minutes 27 seconds, the road to the river takes nearly 9 minutes 33 seconds

Step-by-step explanation:

Use the formula $D=r\cdot t,$ where D is the distance, r is the rate and t is the time.

Note that 15 minutes $=\dfrac{15}{60}=\dfrac{1}{4}=0.25$ hour.

A. Set up the table as follows:

$\begin{array}{cccc}&\text{Rate}&\text{Time}&\text{Distance}\\ \\\text{To the River}&40\ mph&0.25-t&40(0.25-t)\\\text{From the River}&70\ mph&t&70t\end{array}$

B. The distance covered by cheetah is the same to the river and from the river, so

$40(0.25-t)=70t$

C. Solve this equation:

$40(0.25-t)=70t\\ \\10-40t=70t\\ \\110t=10\\ \\t=\dfrac{10}{110}=\dfrac{1}{11}\ hour$

Now

$\dfrac{1}{11}\ hour = \dfrac{1}{11}\cdot 60\ minutes=\dfrac{60}{11}\ minutes=5\dfrac{5}{11}\ minutes$

Thus, the road from the river takes nearly 5 minutes 27 seconds, the road to the river takes nearly 9 minutes 33 seconds.