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Anni [7]
3 years ago
7

15d^3+30d^2+30d/3d3 what is the answer if you divide the following

Mathematics
1 answer:
lawyer [7]3 years ago
5 0
When you separate them
\frac{15d^{3} }{ {3d}^{3} }  +  \frac{30d^{2} }{ {3d}^{3} }  +  \frac{30d }{ {3d}^{3} }   = x
Solve them separately:
5 +  \frac{10}{d}  +  \frac{10}{ {d}^{2} }  = x
Remove the denominators:
5 + 10 {d}^{ - 1}  + 10 {d}^{ - 2}  = x
Find GCF (Greatest Common Factor):
5(1 + 2 {d}^{ - 1}  + 2 {d}^{ - 2} ) = x
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7% of 200 is what number?​
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Given points A (1, 2/3), B (x, -4/5), and C (-1/2, 4) determine the value of x such that all three points are collinear
AlladinOne [14]

Answer:

x=\frac{83}{50}

Step-by-step explanation:

we know that

If the three points are collinear

then

m_A_B=m_A_C

we have

A (1, 2/3), B (x, -4/5), and C (-1/2, 4)

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

step 1

Find the slope AB

we have

A(1,\frac{2}{3}),B(x,-\frac{4}{5})

substitute in the formula

m_A_B=\frac{-\frac{4}{5}-\frac{2}{3}}{x-1}

m_A_B=\frac{\frac{-12-10}{15}}{x-1}

m_A_B=-\frac{22}{15(x-1)}

step 2

Find the slope AC

we have

A(1,\frac{2}{3}),C(-\frac{1}{2},4)

substitute in the formula

m_A_C=\frac{4-\frac{2}{3}}{-\frac{1}{2}-1}

m_A_C=\frac{\frac{10}{3}}{-\frac{3}{2}}

m_A_C=-\frac{20}{9}

step 3

Equate the slopes

m_A_B=m_A_C

-\frac{22}{15(x-1)}=-\frac{20}{9}

solve for x

15(x-1)20=22(9)

300x-300=198

300x=198+300

300x=498

x=\frac{498}{300}

simplify

x=\frac{83}{50}

8 0
3 years ago
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