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3 years ago

13

Find the equation of the line that passes through (3, 1) and has a y-intercept of –2.

1 answer:

katen-ka-za [31]3 years ago

6 0

Answer:

$1 = m$

Step-by-step explanation:

1 = 3[1] + b

$\displaystyle -2 = b \\ \\ y = x - 2$

Therefore our <em>rate</em><em> </em><em>of</em><em> </em><em>change</em><em> </em>[<em>slope</em>] is authentic.

I am joyous to assist you anytime.

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Solve for area of the shaded region (#61) <br> Pls explain im so confused

BartSMP [9]

Answer: So after reading my explanation you can simply find the area good luck!

Step-by-step explanation:

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3 years ago

Is 0.529 greater than 0.54

attashe74 [19]

No. 0.54 is equal to 0.540

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3 years ago

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42 is 9 more than 3 times a number. what is the number?

yuradex [85]

Equation: 3x+9=42

3x=42-9=33

<span>Answer: x=33/3=11

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</span>

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3 years ago

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Please help if you can:)

geniusboy [140]

Answer:

(-2,17) i think i am not sure

Step-by-step explanation:

8 0

3 years ago

Find the equation of the line that passes through the point of intersection of x + 2y = 9 and 4x -2y = -4 and the point of inter

Rudik [331]

Answer:

$y=-6x+10$

Step-by-step explanation:

The point of intersection of

$x+2y=9...eqn1$

and

$4x-2y=-4...eqn2$

is the solution of the two equations.

We add equation (1) and equation(2) to get,

$x+4x+2y-2y=9+-4$

$\Rightarrow 5x=5$

$\Rightarrow x=1$

We put $x=1$ into equation (1) to get,

$1+2y=9$

$\Rightarrow 2y=9-1$

$\Rightarrow 2y=8$

$\Rightarrow y=4$

Therefore the line passes through the point, $(1,4)$ .

The line also passes through the point of intersection of

$3x-4y=14...eqn(3)$

and

$3x+7y=-8...eqn(4)$

We subtract equation (3) from equation (4) to obtain,

$3x-3x+7y--4y=-8-14$

$\Rightarrow 11y=-22$

$\Rightarrow y=-2$

We substitute this value into equation (4) to get,

$3x+7(-2)=-8$

$3x-14=-8$

$3x=-8+14$

$3x=6$

$x=2$

The line also passes through

$(2,-2)$

The slope of the line is

$slope=\frac{4--2}{1-2} =\frac{6}{-1}=-6$

The equation of the line is

$y+2=-6(x-2)$

$y+2=-6x+12$

$y=-6x+10$ is the required equation

4 0

3 years ago