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svet-max [94.6K]
3 years ago
10

Convert from general form to standard form x^2 + 4y^2 + 6x-40y+9 =0​

Mathematics
1 answer:
Burka [1]3 years ago
7 0

x^2 + 4y^2 + 6x-40y+9 =0\\x^2 + 6x+9+4y^2-40y=0\\x^2+6x+9+4y^2-40y+100-100=0\\(x+3)^2+(2y-10)^2=100

P.S. Hello from Russia

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Answer:

\huge{ \fbox{ \sf{13 \: units}}}

Option C is correct.

Step-by-step explanation:

\star{ \sf{ \: Let \: the \: points \: be \: a \: and \: b}}

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\boxed{ \sf{Distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}

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\mapsto{ \sf{ \sqrt{144 + 25}}}

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Hope I helped!

Best regards! :D

~\text{TheAnimeGirl}

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Step-by-step explanation:

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