The first thing to do is to calculate how many ways you can choose 3 people from a set of eight. In order to do this, we need to use the attached formula.
(The letter 'n' stands for the entire set and 'r' stands for the number of objects we wish to choose.)
So we wish to choose 3 people ('r') form a set of 8 ('n')
combinations = n! / r! * (n - r)!
combinations = 8 ! / (3! * 5!)
combinations = 8 * 7 * 6 * 5! / (3!) * (5!)
combinations = 8 * 7 * 6 / 3 * 2
combinations = 56
Now of those 56 combinations, the 3 people can finish in 6 different ways.
For example, persons A, B and C could finish
ABC or ACB or BAC or BCA or CAB or CBA
So to get the TOTAL combinations we multiply 56 * 6 which equals
336 so the answer is (a)
15x+100=28
x=-6/5
The answer is -6/5
I think the answer is 8. not completely sure tho
Probability red+green
first pick(red) : 7/10
2nd pick( green) : 1/10
the answer maybe like this
prob : 7/10+1/10 = 8/10 =4/5
Answer:
18.6
Step-by-step explanation:
-3(-6.2)
~Expand
-3 * -6.2
~Multiply
18.6
Best of Luck!
