Answer:
3.6
Step-by-step explanation:
HOPE IT HELPS!!!!!!!
Answer:
B. Line A intersects line B at the point (-2,2)
Step-by-step explanation:
y = mx + b
m₁ = 2
-2 = 2 x (-4) + b₁
b₁ = 6
y₁ = 2x₁ + 6 : line₁
point (-2 , 2) : 2 x (-2) + 6 = 2
(-2 , 2) is on line₁
m₂ = (-4 -4 ) / (10 - (-6)) = -8 / 16 = - 1/2
line₂ : (-6 , 4) (10 , -4)
4 = - 1/2 x (-6) + b₂
b₂ = 1
y₂ = -1/2 x + 1 : line₂
point (-2 , 2) -1/2 x (-2) + 1 = 2
prove (-2 , 2) is on line₂ too.
Answer:
False, there are no solutions
Step-by-step explanation:
y = 2x+4
y = 2x+10
The slopes are the same (2) but the y intercepts are different
These lines are parallel with different intercepts
They will never intersect so there are no solutions
find the gradient = change in y/change in X
-5 - -3/-3 - -6
= -2/3
take any two point say -3,-5 and equate to the gradient
Y - 5 /X - 3 = -2/3
cross multiply
3y - 15 = -2x + 6
3y = -2x +6 + 15
3y = -2x + 21
y = -2/3x +7