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3 years ago

14

Sam subtracted 5 from the quotient of a number and 3. Write an algebraic expression to represent the operations that Sam preform

ed

1 answer:

ella [17]3 years ago

4 0

Answer:

(x/3) - 5.

Step-by-step explanation:

Let the number be x.

The quotient of the number and 3 is x/3.

So the expression is:

(x/3) - 5.

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A spherical balloon is being inflated at a rate of 3 cubic inches per second. Determine the change in the rate of the radius.How

Novay_Z [31]

Answer:

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

The radius is changing more rapidly when the diameter is 12 inches.

Step-by-step explanation:

Consider the provided information.

A spherical balloon is being inflated at a rate of 3 cubic inches per second.

The volume of sphere is $V=\frac{4}{3}\pi r^3$

Differentiate the above formula with respect to time.

$\frac{dV}{dt}=4\pi r^2\frac{dr}{dt}$

Substitute the respective values in the above formula,

$3=4\pi 6^2\frac{dr}{dt}$

$\frac{1}{48\pi}=\frac{dr}{dt}$

The rate rate of change of radius is $\frac{1}{48\pi}$ inches per second when the diameter is 12 inches.

When d=16

$3=4\pi 8^2\frac{dr}{dt}$

$\frac{3}{256\pi}=\frac{dr}{dt}$

Thus, the radius is changing more rapidly when the diameter is 12 inches.

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3 years ago

What is the area of the semicircle?

Serggg [28]

Step-by-step explanation:

$Area (semi-circle)= \frac{r^2\pi }{2}$

$A = \frac{(11)^2\pi }{2}$

$A=\frac{121\pi }{2}$

$A=\frac{379.94}{2}$

$A=189.97$

The area of the semi-circle is 189.97

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Find the area of a circle with the radius of 3.5

VARVARA [1.3K]

Area = 38.48 hope this helps

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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