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Zepler [3.9K]
3 years ago
10

What is the coefficient of q (2/3q-3/4) and -1/6q-r)

Mathematics
1 answer:
kirza4 [7]3 years ago
4 0
The coefficient in (2/3q-3/4) is 2/3 and in (-1/6q-r) is -1/6
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Artist 52 [7]

Answer:

18 hdhb

Step-by-step explanation:

8 0
3 years ago
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3. Given the directed line segment AB, with endpoints A20, 6) and B(-16, 50), find the point Q
garri49 [273]

The point Q that partitions the line segment is Q(2,28)

Given that the directed line segment AB, with endpoints A(20, 6) and B(-16, 50) and divide the segment into a 1:1 ratio.

A line segment is a part of a line bounded by two distinct endpoints and containing all the points of the line segment between its endpoints.

We will find the point Q by using the section formula that is

Q(x,y)=((mx₂+nx₁)/(m+n),(my₂+ny₁)/(m+n))

The given ratio is m:n=1:1 and the points (x₁,y₁)=(20,6) and (x₂,y₂)=(-16,50).

Firstly, we will find the point Q for x-axis, we get

Q(x)=(mx₂+nx₁)/(m+n)

Q(x)=(1×(-16)+1×20)/(1+1)

Q(x)=(-16+20)/2

Q(x)=4/2

Q(x)=2

Now, we will find the point Q for y-axis, we get

Q(y)=(my₂+ny₁)/(m+n)

Q(y)=(1×50+1×6)/(1+1)

Q(y)=(50+6)/2

Q(y)=56/2

Q(y)=28

The point Q that partitions the line segment is Q(x,y)=(2,28)

Hence, point Q partitions this segment into a 1:1 ratio with directed line segment AB, with endpoints A(20, 6) and B(-16, 50) is Q(2,28).

Learn more about the line segment from here brainly.com/question/9034900

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8 0
2 years ago
What is the actual slope of this line?
-BARSIC- [3]

Answer:

  -4

Step-by-step explanation:

The line has a "rise" between the two points of -4 units for a "run" of +1 unit. The slope is the ratio ...

  m = rise/run = -4/1 = -4.

The slope is -4.

_____

<em>Additional comment</em>

A "whole number" must be non-negative. Here, the slope is negative. If you're restricted to "a fraction or a whole number", then the appropriate answer is the fraction -4/1. We suspect that "integer" is meant where "whole number" is used.

5 0
3 years ago
Rksheet
VLD [36.1K]

See below for the terms, coefficients, and constants in the variable expressions

<h3>How to determine the terms, coefficients, and constants in the variable expressions?</h3>

To determine the terms, coefficients, and constants, we use the following instance:

ax + by + c

Where the variables are x and y

  • Then the terms are ax, by and c
  • The coefficients are a and b
  • The constant is c

Using the above as guide, we have:

A) 2b + 2ac+5

  • Terms: 2b, 2ac, 5
  • Coefficient: 2, 2 and 5
  • Constant 5

B) 34abx + 16y +1

  • Terms: 34abx, 16y, 1
  • Coefficient: 34ab, 16
  • Constant: 1

C) st +4u + v

  • Terms: st, 4u, v
  • Coefficient: 4

D) 14xy + 6

  • Terms: 14xy, 6
  • Coefficient: 14, 6
  • Constant 6

E) 14x + 12y

  • Terms: 14x, 12y
  • Coefficient: 14, 12

F) 3+ 6-7+a

  • Terms: 3, 6, -7, a
  • Coefficient: 1
  • Constant: 3, 6, -7

Read more about terms, coefficients, and constants at:

brainly.com/question/14625487

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5 0
1 year ago
3252614683754629158741032465x93756356872264881+432757232878247-3243566=
Paul [167]

Answer:

bout 7

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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