1.<AFC
2.<AFD
3.<AFE
4.<AFB
#5, 6 and 7
m<BAE = 59
m<BAC + m<CAD + m<DAE = m<BAE
4x - 20 + x + 12 + x + 1 = 59
6x - 7 = 59
6x = 59 + 7
6x = 66
x = 11
m<BAC = 4x - 20 = 4(11) - 20 = 24
m<CAD = x + 12 = 11 + 12 = 23
m<BAE = x + 1 = 11 + 1 = 12
answer
5.
m<BAC = 24
6.
m<CAD = 23
7.
m<BAE = 12
#8, 9 and 10
m<BAE = 130
m<BAC + m<CAD + m<DAE = m<BAE
3x - 10 + 2x + 5 + x + 15 = 130
6x + 10 = 130
6x = 120
x = 20
m<BAC = 3x - 10 = 3(20) - 10 = 60 -10 = 50
m<CAD = 2x + 5 = 2(20) + 5 = 40 + 5 = 45
m<DAE = x + 5 = 20 + 15 = 35
answer
8.
m<BAC = 50
9.
m<CAD = 45
10.
m<DAE = 35
Answer:
Connect the arc markings to complete the perpendicular bisector
.
I took the test and got it right.
X+5y=-11 (1)
2x-3y=17 (2)
2(1)-(2)
2x+10y-2x+3y=-22-17
13y=-39
y=-3
Sub y=-3 in (1)
x+5(-3)=-11
x=4
So x+y= -3+4 =1
Answer: The cone can hold 18.84 cubic inches of ice cream.
Step-by-step explanation:
Hi, to answer this question we have to find the volume of a cone, using only the height (h) and the radius(r) values.
Volume of a cone (V) = 1/3 π r² h
Replacing with the values given:
V = 1/3 (3.14) (3)² 2
Solving:
V = 1/3 (3.14) (9) 2
V = 18.84 cubic inches
In conclusion, the cone can hold 18.84 cubic inches of ice cream.
Answer:
Step-by-step explanation:
This inequality is quite simple to solve.
Just multiply both sides by four and you have your answer:
Hope this helps!
