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SIZIF [17.4K]
3 years ago
8

7−s/2>3 Solve for the inequality PLZZZZ help I am struggling with khan academy

Mathematics
1 answer:
Whitepunk [10]3 years ago
7 0

Answer:

Step-by-step explanation:

Let's solve your inequality step-by-step.

7 - s/2 > 3

Step 1: Simplify both sides of the inequality.

−1 /2 s + 7 > 3

Step 2: Subtract 7 from both sides.

−1 /2 s + 7 − 7 > 3 − 7

−1 /2 s > − 4

Step 3: Multiply both sides by 2/(-1).

( 2 /−1 ) * ( −1/ 2 s) > ( 2/ −1 )*(−4)

s<8

Answer:

s<8

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What is the x and y equal in y=8x+1 and y=3x+26
Alla [95]

Answer:

x=5, y=41

Step-by-step explanation:

Because both equations are equal to Y, you can set them equal to each other like this:

8x+1=3x+26

From here, solve for x:

1. 5x+1=26

2. 5x=25

3. x=5

Once you have x, plug it back in to one of the original equations:

y=8(5)+1

y=41 and then you have your answer

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Step-by-step explanation:

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3 years ago
35 of the apartments have a balcony and 55 of them don't. An apartment is randomly selected as part of a survey. What is the pro
kobusy [5.1K]

Answer:

39%

Step-by-step explanation:

It is given that 35 apartments have balconies in them.

While 55 apartments do not have balconies in them.

Total number of balconies is the sum of the apartments. i.e. 35 + 55

                                                                                             = 90 apartments

Therefore for the survey when an apartment is randomly selected, the percentage of the probability of the apartment to have a balcony can be found out by dividing 35 by 90 and then multiply by 100.

i.e.

$=\frac{35}{90}$

= 0.38888888

Multiplying by 100, we get

= 0.388888 x 100

= 38.8888 %

= 39 %

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3 years ago
This is a variation acitivity:
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\bf \qquad \qquad \textit{direct proportional joint variation} \\\\ \textit{\underline{y} varies jointly with \underline{x} and \underline{z}}\qquad \qquad y=kxz\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}


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