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Alona [7]
3 years ago
15

Which of these best describes the Pythagorean theorem?

Mathematics
1 answer:
xxMikexx [17]3 years ago
3 0

Answer:

A)

Step-by-step explanation:

The theorem states that if a right triangle has two sides equal to a and b, and a hypotenuse equal to c, then a squared plus b squared equals c squared.

the square of the length of the hypotenuse of a right triangle equals the sum of the squares of the lengths of the other two sides.

hope this help please mark me

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An athlete jumps vertically at t=0 from the ground and stays in the air for one second before landing on the ground again. The h
lawyer [7]

Answer:

The answer is B

Step-by-step explanation:

I just did the Quick Check, the attachment is the answer, np.

3 0
3 years ago
Q # 7 please help to solve
Neko [114]
The fourth choice - 5/104.

In one cube, there are 3 even numbers - 2,4,6. For two cubes, the total probability is 36.
   3*3 / 36 = 9/36

For letters, there are five vowels over 26 letters = 5 / 26

Multiply the two probabilities to get the probability of rolling two even numbers and selecting one of the vowels.
   9/36 * 5/26 = 5/104
   
6 0
3 years ago
Xiao teacher asked him to rewrite the sum 60+90 as the product of the GCF of the two numbers and a sum Xiao wrote 3(20+30) what
GrogVix [38]
The\ mistake:GCF(60;\ 90)\ isn't\ 3\ just\ 30.\\\\Correct\ answer:60+90=30(2+3)
8 0
3 years ago
Of the 60 books on a bookshelf, 24 are nonfiction, 9 are realistic-fiction, 11 are reference, and the remaining books are fantas
luda_lava [24]

Answer:

16

Step-by-step explanation:

You would first add all the diffrent types of books all together.

24+9+11= 44

Next subtract that from the total number of books to get how many fantasy books you have.

60-44= 16

7 0
3 years ago
Read 2 more answers
The roots of a quadratic equation ax2+bx+c=0 are 3+sqrt2 and 3−sqrt2. Find the values of b and c assuming that a=1.
slamgirl [31]

Answer:

b=-6\\c=7

Step-by-step explanation:

we know that

The general equation of a quadratic function in factored form is equal to

y=a(x-x_1)(x-x_2)

where

a is a coefficient of the leading term

x_1 and x_2 are the roots

we have

a=1\\x_1=3+\sqrt{2}\\x_2=3-\sqrt{2}

substitute

y=(1)(x-(3+\sqrt{2}))(x-(3-\sqrt{2}))

Applying the distributive property convert to expanded form

y=x^2-x(3-\sqrt{2})-x(3+\sqrt{2})+(3+\sqrt{2})(3-\sqrt{2})

y=x^2-(3x-x\sqrt{2})-(3x+x\sqrt{2})+(9-2)

y=x^2-3x+x\sqrt{2}-3x-x\sqrt{2}+7

y=x^2-6x+7

therefore

b=-6\\c=7

7 0
3 years ago
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