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Black_prince [1.1K]
3 years ago
12

Express the area of a rectangle as a function of the width w if the width of the rectangle is twice its length

Mathematics
1 answer:
seraphim [82]3 years ago
4 0
Hope tihs helps :D :Ddddddddddddddd

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Round 145.98 to the nearest ones
Evgesh-ka [11]
145.98 is rounded to 146.00.

Hope this helps you! :)
5 0
3 years ago
Read 2 more answers
Figure 3<br> 2n + 10<br> 140<br> 4n -40<br> 80<br> 2n<br> 3n - 20<br> I need help
abruzzese [7]

Answer:

2n +10= 140

4n- 40= 80

2n= 3n - 20

Step-by-step explanation:

it is the am progression or sum progression

3 0
2 years ago
Can anyone please explain? Need some help :)
DedPeter [7]

Answer:

93.5 square units

Step-by-step explanation:

Diameter of the Circle = 12 Units

Therefore:

Radius of the Circle = 12/2 =6 Units

Since the hexagon is regular, it consists of 6 equilateral triangles of side length 6 units.

Area of the Hexagon = 6 X Area of one equilateral triangle

Area of an equilateral triangle of side length s = \dfrac{\sqrt{3} }{4}s^2

Side Length, s=6 Units

\text{Therefore, the area of one equilateral triangle =}\dfrac{\sqrt{3} }{4}\times 6^2\\\\=9\sqrt{3} $ square units

Area of the Hexagon

= 6 X 9\sqrt{3} \\=93.5$ square units (to the nearest tenth)

7 0
3 years ago
Solve the following equation for the
Akimi4 [234]
Divide -3
-3/-3a = 15/-3
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5 0
3 years ago
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Use differentials to estimate the amount of metal in a closed cylindrical can that is 26 cm high and 10 cm in diameter if the me
Afina-wow [57]

Answer:

The estimated amount of metal in the can is 87.96 cubic cm

Step-by-step explanation:

We can find the differential of volume from the volume of a cylinder equation given by

V= \pi r^2 h

Thus that way we will find the amount of metal that makes up the can.

Finding the differential.

A small change in volume is given by:

dV =\cfrac{\partial V}{\partial h} dh + \cfrac{\partial V}{\partial r} dr

So finding the partial derivatives we get

dV =\pi r^2 dh + \pi 2r h dr

dV =\pi r^2 dh + 2\pi r h dr

Evaluating the differential at the given information.

The height of the can is h = 26 cm, the diameter is 10 cm, which means the radius is half of it, that is r = 5 cm.

On the other hand the thickness of the side is 0.05 cm that represents dr = 0.05 cm, and the thickness on both top and bottom is 0.3 cm, thus dh = 0.3 cm +0.3 cm which give us 0.6 cm.

Replacing all those values on the differential we get

dV =\pi 5^2 (0.6) + 2\pi (5) (26) (0.05)

That give us

V= 28 \pi  \, cm^3

Or in decimal value

\boxed{dV= 87.96 \, cm^3}

Thus the volume of metal in the can is 87.96 cubic cm.

6 0
3 years ago
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