Answer:
Yes, Mina is correct
Step-by-step explanation:
Let the triangles be A and B
Given
Triangle A:

Triangle B:

Required
Is Mina's claim correct?
First, we calculate the third angle in both triangles.
For A:


For B:


For triangle A, the angles are: 34, 57 and 89
For triangle B, the angles are: 34, 57 and 89
<em>Since both triangles have the same angles, then by the postulate of AAA (Angle-Angle-Angle), the triangles are similar.</em>
 
        
             
        
        
        
I will give you my solution down here
3x-x=2+4
2x=6
x=3
        
             
        
        
        
1024 can be factored into 
<span>2(512) </span>
<span>=2^2(256) </span>
<span>=2^3(128) </span>
<span>=2^4(64) </span>
<span>=2^5(32) </span>
<span>=2^6(16) </span>
<span>=2^10 </span>
<span>Therefore, </span>
<span>√1024 = √(2^10) = 2^5 = 32</span>
        
             
        
        
        
Answer:
y=2x+6
Step-by-step explanation:
Graph the coordinates
Go up to over one or down two left on
Get your y-intercept 
put in y=mx+b