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padilas [110]
3 years ago
13

determine the vertex and axis of symmetry for the following: f(x) = 2x to the power of 2 - 12x + 24 ?

Mathematics
1 answer:
Vikki [24]3 years ago
7 0

Answer:

vertex = (3,24)  Axis of symmetry = 3

Step-by-step explanation:

Use the vertex formula to find x: x=-b/2(a)

x= 12/2(2) = 3 (this is your axis of symmetry)

Substitute 3 for x in the equation to get y: y = 42

Once you have both x and y you have your vertex.

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Find the value of X in each of the following X/3-2=6 <br>X/5+1 =5<br><br>please help me ​
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Answer:

a) x = 24

b) x = 20

Step-by-step explanation:

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3 years ago
More Information From the Online Dating Survey A survey conducted in July 2015 asked a random sample of American adults whether
svet-max [94.6K]

Answer:

90% confidence interval for the proportion of all US adults ages 55 to 64 to use online dating is [0.095 , 0.148].

Step-by-step explanation:

We are given that a survey conducted in July 2015 asked a random sample of American adults whether they had ever used online dating.

The survey included 411 adults between the ages of 55 and 64, and 50 of them said that they had used online dating.

Firstly, the pivotal quantity for 90% confidence interval for the population proportion is given by;

                                P.Q. =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of adults who said that they had used online dating =  \frac{50}{411}  = 0.122

n = sample of adults between the ages of 55 and 64 = 411

p = population proportion of all US adults ages 55 to 64 to use online dating

<em>Here for constructing 90% confidence interval we have used One-sample z proportion statistics.</em>

<u>So, 90% confidence interval for the population proportion, p is ;</u>

P(-1.645 < N(0,1) < 1.645) = 0.90  {As the critical value of z at 5% level

                                                  of significance are -1.645 & 1.645}  

P(-1.645 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 1.645) = 0.90

P( -1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.90

P( \hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.90

<u>90% confidence interval for p</u> = [\hat p-1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }, \hat p+1.645 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

= [ 0.122-1.645 \times {\sqrt{\frac{0.122(1-0.122)}{411} } } , 0.122+1.645 \times {\sqrt{\frac{0.122(1-0.122)}{411} } } ]

 = [0.095 , 0.148]

Therefore, 90% confidence interval for the proportion of all US adults ages 55 to 64 to use online dating is [0.095 , 0.148].

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