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3 years ago

If y=30 when x=6 what is the value of y when x=12

Mathematics

2 answers:

storchak [24]3 years ago

7 0

Answer:

Step-by-step explanation:

it doubled the x so double y

Ne4ueva [31]3 years ago

5 0

Answer:

Step-by-step explanation:

tge question wasn't really clear btw

You might be interested in

Find the slope of the line throgh each pair of points

svlad2 [7]

Answer:

19/24

Step-by-step explanation:

slope = rise/run = (y1 - y2) / (x1 - x2)

s = (19 - 0) / (8 - -16)

s = 19/24

4 0

3 years ago

From 1995 - 2008 in the US 648 people were struck by lightening. 531 of them were men. You want to see if this observation diffe

Gre4nikov [31]

Answer:

Because z is higher than any given value in the chart we come to the conclusion To reject null hypothesis

Step-by-step explanation:

Sample proportion = p= 531/648 = 0.8194

This is the proportion of men that were hit by lightening

Null hypothesis: H0: p = 0.5

Alternate hypothesis: H1: p ≠ 0.5

Test statistics z = 0.8194-0.5/(√0.5x0.5/648)

= 0.8194-0.5/√0.0003858

= 0.3194/0.019642

= 16.26

Since the z > 1.96 (at 5% significance) we reject the null hypothesis.

Therefore in conclusion we say z is higher than given values in the chart so we reject null hypothesis.

Please check attachment!

3 0

4 years ago

1) Given: circle k(O), ED= diameter ,m∠OEF=32°, m(arc)EF=(2x+10)° Find: x

qaws [65]

1. The major arc ED has measure 180 degrees since ED is a diameter of the circle. The measure of arc EF is $(2x+10)^\circ$ , so the measure of arc DF is

$m\widehat{DF}=360^\circ-180^\circ-(2x+10)^\circ=(170-2x)^\circ$

The inscribed angle theorem tells us that the central angle subtended by arc DF, $\angle DOF$ , has a measure of twice the measure of the inscribed angle DEF (which is the same angle OEF) so

$m\angle DOF=2m\angle OEF=64^\circ$

so the measure of arc DF is also 64 degrees. So we have

$170-2x=64\implies106=2x\implies\boxed{x=53}$

###

2. Arc FE and angle EOF have the same measure, 56 degrees. By the inscribed angle theorem,

$m\angle EOF=2m\angle EDF\implies56^\circ=2m\angle EDF\implies m\angle EDF=28^\circ$

Triangle DEF is isosceles because FD and ED have the same length, so angles EFD and DEF are congruent. Also, the sum of the interior angles of any triangle is 180 degrees. It follows that

$m\angle EFD+m\angle EDF+m\angle DEF=180^\circ\implies\boxed{m\angle EFD=76^\circ}$

Triangle OFE is also isosceles, so angles EFO and FEO are congruent. So we have

$m\angle EFO+m\angle FEO+m\angle EOF=180^\circ\implies\boxed{m\angle EFO=62^\circ}$

7 0

3 years ago

The perimeter and area of each figure:<br> a. A square with a side length of 3.5 inches.

Anna11 [10]

$3.5 \times 3.5 = 12.25 \: for \: are \\ 3.5 \times 4 = 14 \: for \: perimeter$

5 0

4 years ago

The height 'h' (in feet) of a ball in a baseball game can be modeled by h = -16t² + 28t + 8 , where 't' is the time (in seconds)

lidiya [134]

Answer:

a) No. t < 0 is not part of the useful domain of the function

b) 2.0 seconds

Step-by-step explanation:

a) A graph of the function is shown below. It shows t-intercepts at t=-0.25 and t=2.0. We presume that t is measured forward from some event such as the ball being thrown or hit. The model's predicted ball location has no meaning prior to that event, when values of t are negative.

b) It is convenient to use a graphing calculator to find the t-intercepts. Or, the equation can be solved for h=0 any of several ways algebraically. One is by factoring.

h = 0 = -16t² +28t +8 . . . . . . . . . . . . the ball hits the ground when h = 0

0 = -4(4t² -7t -2) = -4(4t +1)(t -2)

This has t-intercepts where the factors are zero, at t=-1/4 and t=2.

The ball will hit the ground after 2 seconds.

4 0

3 years ago