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3 years ago

Need help with this question please

Mathematics

1 answer:

sineoko [7]3 years ago

8 0

Answer:

Step-by-step explanation:

The vector GH has horizontal and vertical components of 5 and 12. You recognize that these are part of the Pythagorean triple (5, 12, 13), so the length of GH will be 13.

_____

In case you haven't run across this fun fact often enough to remember it, you can compute the length from the distance formula:

d = √((x2-x1)² +(y2-y1)²) = √((-1-4)² +(10-(-2))²) = √((-5)² +12²)

d = √(25+144) = √169 = 13

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The total number of subsets of {A, B, C} is _____.. . . a.6. b.7. c.8

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The total number of subsets of {A, B, C} is 8. It can be found by cubing 2 and the resulting answer will definitely be 8. The correct option among all the options that are given in the question is the third option or option "c". I hope that this answer has come to your help.

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3 years ago

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The perimeter of a rectangular pen is 136 meters. If the length is 5 meters more than twice the width, what are the dimensions o

Sati [7]

Answer: width = 21, length = 47

Step-by-step explanation:

Length (L) = 2w + 5

width (w) = w

Perimeter (P) = 136

P = 2L + 2w

136 = 2(2w + 5) + 2w substituted the given values above

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3 years ago

Solve the system by substitution. x= -5y - 6 5x – 3y = -2 What’s is the solution?

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3 years ago

Unit 4 Lesson 13 exit ticket (please help me im getting stressed with this)

Illusion [34]

Answer:

1. is A

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Step-by-step explanation:

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2 years ago

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10 points!!! please help :(

daser333 [38]

To complete the identity, we need these fundamental identities:

$1)\displaystyle{sec(x)=\frac{1}{cos(x)}$

$2) cos(x-y)=cos(x)cos(y)+sin(x)sin(y)$

$\displaystyle{csc(x)= \frac{1}{sin(x)}$

Thus, by identity 1 we have:

$\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}$

by identity :

$\displaystyle{cos(\frac{ \pi }{2}-\theta)=cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)$

recall the values :

$\displaystyle{ sin(\frac{ \pi }{2})^R=sin(90^o)=1\\\\$

$\displaystyle{ cos(\frac{ \pi }{2})^R=cos(90^o)=0$ ,

so:

$cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)=0+sin(\theta)=sin(\theta)$

Putting all these together, we have:

$\displaystyle{ sec( \frac{ \pi }{2}-\theta )= \frac{1}{cos(\frac{ \pi }{2}-\theta)}= \frac{1}{cos(\frac{ \pi }{2})cos(\theta)+sin(\frac{ \pi }{2})sin(\theta)}= \frac{1}{sin(\theta)}}$

which is equal to $csc(\theta)$ , by identity 3

Answer: D

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3 years ago