Answer:
tons of high steel and 
tons of low steel
Step-by-step explanation:
Let x be the number of tons of high grade steel and y be the number of tons ow low grade steel needed.
In x tons of high grade steel there are
tons of iron
tons of magnese
In y tons of low grade steel there are
tons of iron
tons of magnese
NASA orders 500 tons of steel, so
and specifies that it must be in the proportion 80% iron and 20% magnese, so
From the first equation,
Substitute it into the second equation:
Answer:
9 miles
Step-by-step explanation:
mean is calculated as
mean = 
, then
= 5.7 ( multiply both sides by 10 )
sum = 57
let x be the distance he needs to cover so mean is 6 , that is
= 6 ( multiply both sides by 11 )
sum + x = 66 , that is
57 + x = 66 ( subtract 57 from both sides )
x = 9
That is he would have to run 9 miles
Answer:
i do no sorry plz i have exam in online so sorry
Answers:
Vertical asymptote: x = 0
Horizontal asymptote: None
Slant asymptote: (1/3)x - 4
<u>Explanation:</u>
d(x) = 
= 
Discontinuities: (terms that cancel out from numerator and denominator):
Nothing cancels so there are NO discontinuities.
Vertical asymptote (denominator cannot equal zero):
3x ≠ 0
<u>÷3</u> <u>÷3 </u>
x ≠ 0
So asymptote is to be drawn at x = 0
Horizontal asymptote (evaluate degree of numerator and denominator):
degree of numerator (2) > degree of denominator (1)
so there is NO horizontal asymptote but slant (oblique) must be calculated.
Slant (Oblique) Asymptote (divide numerator by denominator):
- <u>(1/3)x - 4 </u>
- 3x) x² - 12x + 20
- <u>x² </u>
- -12x
- <u>-12x </u>
- 20 (stop! because there is no "x")
So, slant asymptote is to be drawn at (1/3)x - 4
Answer:
y = 3/5 x + 2.
Step-by-step explanation:
Use the point-slope equation of a straight line:
y - y1 = m (x - x1) where m = the slope amd (x1, y1) is a point on the line.
Here:
m = (5- (-1)) / (5 - (-5))
= 6/10
= 3/5.
Substituting for m and (5, 5):
y - 5 = 3/5(x - 5)
y - 5 = 3/5x - 3
y = 3/5 x + 2.
