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3 years ago

What is the answer to this problem -2b+6=-2b-2b?

1 answer:

8 0

6 = -2b (cancel -2b on both sides)

6/-2 = b (divide both sides by -2)

-3 = b (simplify 6/2 to 3)

now switch sides

Answer: b = -3

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Line FG goes through the points (4,9) and (1,3). Which equation represents a line that is perpendicular to FG and passes through

stiks02 [169]

Answer:

$x + 2y= 2$

Step-by-step explanation:

Given

Points:

$F = (4,9)$

$G = (1,3)$

Required

Determine the equation of line that is perpendicular to the given points and that pass through $(2,0)$

First, we need to determine the slope, m of FG

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where

$F = (4,9)$ --- $(x_1,y_1)$

$G = (1,3)$ --- $(x_2,y_2)$

$m = \frac{3 - 9}{1 - 4}$

$m = \frac{- 6}{- 3}$

$m =2$

The question says the line is perpendicular to FG.

Next, we determine the slope (m2) of the perpendicular line using:

$m_2 = -\frac{1}{m}$

$m_2 = -\frac{1}{2}$

The equation of the line is then calculated as:

$y - y_1 = m_2(x - x_1)$

Where

$m_2 = -\frac{1}{2}$

$(x_1,y_1) = (2,0)$

$y - 0 = -\frac{1}{2}(x - 2)$

$y = -\frac{1}{2}(x - 2)$

$y = -\frac{1}{2}x + 1$

Multiply through by 2

$2y = -x + 2$

Add x to both sides

$x + 2y= -x +x+ 2$

$x + 2y= 2$

Hence, the line of the equation is $x + 2y= 2$

8 0

3 years ago

Read 2 more answers

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boyakko [2]

Answer:

Step-by-step explanation:

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

Find the sum of the first four terms of the geometric sequence shown below. 4, 4/ 3, 4/9, ...

user100 [1]

It's evident that the first four terms are 4, 4/3, 4/9, and 4/27. So the fourth partial sum of the series is

$S_4=4+\dfrac43+\dfrac49+\dfrac4{27}$

It's as easy as adding up the fractions, but I bet this is supposed to be an exercise in taking advantage of the fact that the series is geometric and use the well-known formula for computing such a sum.

Multiply the sum by 1/3 and you have

$\dfrac13S_4=\dfrac43+\dfrac49+\dfrac4{27}+\dfrac4{81}$

Now subtracting this from $S_4$ gives

$S_4-\dfrac13S_4=4-\dfrac4{81}$

That is, all the matching terms will cancel. Now solving for $S_4$ , you
have

$\dfrac23S_4=4\left(1-\dfrac1{81}\right)$
$S_4=6\left(1-\dfrac1{81}\right)$
$S_4=\dfrac{480}{81}=\dfrac{160}{27}$