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8090 [49]
2 years ago
6

Wich of the following equations would NOT contain the point (4,12)

Mathematics
1 answer:
nlexa [21]2 years ago
8 0

Given:

The given point is (4,12).

To find:

The equation that would NOT contain the point (4,12).

Solution:

We need to check each equation for the point (4,12).

In option A, the given equation is:

y=-2x+20

Putting x=4, we get

y=-2(4)+20

y=-8+20

y=12

This equation contains the point (4,12).

In option B, the given equation is:

y=\dfrac{1}{2}x+8

Putting x=4, we get

y=\dfrac{1}{2}(4)+8

y=2+8

y=10

This equation does not contain the point (4,12).

In option C, the given equation is:

y=-\dfrac{1}{2}x+14

Putting x=4, we get

y=-\dfrac{1}{2}(4)+14

y=-2+14

y=12

This equation contains the point (4,12).

In option D, the given equation is:

y=\dfrac{3}{4}x+9

Putting x=4, we get

y=\dfrac{3}{4}(4)+9

y=3+9

y=12

This equation contains the point (4,12).

Only the equation in option B does NOT contain the point (4,12). Therefore, the correct option is B.

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Two families go skiing on a Saturday. One family purchases three adult lift tickets and four lift tickets for $188. Another fami
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Answer:using elimination to solve for x

9x +6y = 3*134    | Multiplying 1st equation by 3

-4x -6y = -2*146   | Multiplying 2nd equation by -2

   5x = 3*134 - 2*146

   5x = $110

    x = $22,  the cost of the youth ticket

Step-by-step explanation:This question Sets Up two equations with 2 unknowns        

Let x and y represent the cost of the youth and adult ticket respectively

Question states***

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7 0
3 years ago
Determine whether −2 is a zero (root) of the function:
lianna [129]

Answer:

The answer to your question is No

Step-by-step explanation:

Data

function f(x) = 2x³ + x² - 10x - 12

To know if a number is a root of a function, evaluate the function on that number, if the result is zero, then that number is a root.

Substitution          

               f(-2) = 2(-2)³ + (-2)² - 10(-2) - 12

Simplification          

               f(-2) = 2(-8) + 4 + 20 - 12

               f(-2) = -16 + 4 + 20 - 12

               f(-2) = -28 + 24

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-2 is not a root that the function.

5 0
3 years ago
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At noon, ship A is 170 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 20 km/h. How fast is
garik1379 [7]
Check the picture below.

now, keep in mind that ship B is going at 20kph, thus from noon to 4pm, is 4 hours, so it has travelled by then 20 * 4 or 80 kilometers, thus b = 80.

whilst the ship B is moving north, the distance "a" is not really changing, and thus is a constant, that matters because the derivative of a constant is 0.

\bf c^2=a^2+b^2\implies \stackrel{chain~rule}{2c\cfrac{dc}{dt}}=0+2b\cfrac{db}{dt}\implies \cfrac{dc}{dt}=\cfrac{b\frac{db}{dt}}{c}
\\\\\\
\begin{cases}
\frac{db}{dt}=20\\
c=10\sqrt{353}\\
b=80
\end{cases}\implies \cfrac{dc}{dt}=\cfrac{80\cdot 20}{10\sqrt{353}}\implies \cfrac{dc}{dt}=\cfrac{160}{\sqrt{353}}
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\textit{and rationalizing the denominator}\implies \cfrac{160\sqrt{353}}{353}

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3 years ago
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kkurt [141]

Answer:

Step-by-step explanation:

Here's what you write:

    5

---------- = 5(2/1) = 5(2) = 10

  (1/2)

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