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3 years ago

Select the two values of x that are roots of this equation. 2x-5=-3x^2

Mathematics

1 answer:

lakkis [162]3 years ago

3 0

Answer:

A & D

Step-by-step explanation:

=> 3x²+2x-5 = 0

=> Using Mid-term Break Formula

=> 3x²-3x+5x-5 = 0

=> 3x(x-1)+5(x-1) = 0

=> (3x+5)(x-1) = 0

Either,

3x+5 = 0 OR x-1 = 0

x = $-\frac{5}{3}$ OR x = 1

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The first three terms of a geometric sequence are

Lisa [10]

Answer:

a4 = 128

a5 = -512

Step-by-step explanation:

a1= -2

q= (-1)^(n+1) × 4

a4 = a1q³ = (-2) (-4)³ = -2 × -64 = +128

a5 = a1q⁴ = (-2) (-4)⁴ = -2 × 256 = -512

3 0

2 years ago

To watch the video

Anettt [7]

Answer:

The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.

Step-by-step explanation:

Let us take the point of projection of the ball as origin of the coordinate system, the upward direction as positive and down direction as negative.

Initial velocity u with which the ball is projected upwards = + 120 ft/s

Uniform acceleration a acting on the ball is to acceleration due to gravity = - 32 ft/s²

The ball shall keep rising tills its velocity becomes zero. Let it rise to a height h feet from point of projection.

Using the formula:

v² - u² = 2 a h,

where

u = initial velocity of the ball = +120 ft/s

v = final velocity of the ball at the highest point = 0 ft/s

a = uniform acceleration acting on the ball = -32 ft/s²

h = height attained

Substituting the values we get;

0² - 120² = 2 × (- 32) h

=> h = 120²/2 × 32 = 225 feet

The height of the ball from the ground at its highest point = 225 feet + 12 feet = 237 feet.

7 0

3 years ago

How do I graph y=0.17x?

Tomtit [17]

Answer: you can use desmos and type it in just like that a graph will pop up. Go to google and type in desmos

Step-by-step explanation:

3 0

3 years ago

This trapezium is drawn on a centimetre grid. Find the area of the trapezium.

aivan3 [116]

Answer:

20 unit²

Step-by-step explanation:

A trapezium is given to us on the grid and we need to find out the area of the trapezium . In order to find the area , we need to find the measure of the parallel sides and the distance between the parallel sides.

From the grid :-

$\rm\implies Side_1 = 7 \ units$

$\rm\implies Side_2 = 3 \ units$

$\rm\implies \perp \ Distance =4 \ units$

Now here we got the two parallel sides of the trapezium and the distance between the two parallel sides. Now we can find the area as ,

$\rm\implies Area_{Trapezium}= \dfrac{1}{2}\times ( s_1 + s_2) \times \perp \ Distance \\\\\rm\implies Area = \dfrac{1}{2} \times ( 7 + 3 ) \times 4 \ unit^2 \\\\\rm\implies Area = \dfrac{1}{2} \times ( 10) \times 4 \ unit^2 \\\\\rm\implies\boxed{\rm Area = 20 \ unit^2}$