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Stells [14]
3 years ago
10

create a linear function f(x), whose graph has the given slope that meets the given condition. slope of -7, f(-5)=2

Mathematics
1 answer:
sergejj [24]3 years ago
8 0
Our goal is to fit the given information into the slope-intercept form.
y=mx+b

We can place the slope in 'm.'
y= -7x+b

Then, input the values for the x and y.
2= -7(-5)+b
2=35+b
b=2-35
b= -33

'b' is the intercept, so now that we know that, we can plug in all the values and find our final equation.

y= -7x -33

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What is the product?<br> (2x-1)(x+4)<br> 2x²-4<br> 0<br> 2x²+4<br> 0<br> 2x² + 7x-4<br> 2x² – 7x-4
vladimir2022 [97]

Answer:

C) 2x^2+7x-4

Step-by-step explanation:

(2x-1)(x+4)=2x^2-x+8x-4=2x^2+7x-4

3 0
3 years ago
Read 2 more answers
Mhanifa please help with this I find it super difficult! Thanks! I will mark brainliest! Random answers will be reported !
Artyom0805 [142]

Answer:

a)

The point that is equidistant to all sides of a triangle is called the <u>incenter</u>.

The incenter is located at the intersection of bisectors of the interior angles of a triangle.

b)

The point that is equidistant to all vertices of a triangle is called the <u>circumcenter</u>.  

The circumcenter is located at the intersection of perpendicular bisectors of the sides of a triangle.

c)

<em>See the attachment</em>

The blue lines and their intersection shows the incenter.

The red lines and their intersection shows the circumcenter.

As we see the red point- the <u>circumcenter </u>is closer to vertex B.

4 0
3 years ago
The box-and-whisker plot below shows the numbers of text messages received in one day by students in the seventh and eighth grad
Leya [2.2K]
<h3><u>Answer with explanation:</u></h3>

From the box and whisker plot of seventh grade we have:

The minimum value =6

First quartile or lower quartile i.e. Q_1 = 14

Median or second quartile i.e. Q_2 = 18

Third quartile or upper quartile i.e. Q_3 =22

and maximum value = 26

From the box and whisker plot of eighth grade we have:

The minimum value =22

First quartile or lower quartile i.e. Q_1 = 26

Median or second quartile i.e. Q_2 = 30

Third quartile or upper quartile i.e. Q_3 = 34

and maximum value = 38

a)

The overlap of the two sets of data is as follows.

  • The upper quartile or third quartile of seventh grade is same as the minimum value of the data of eighth grade.
  • And the maximum value of seventh grade is same as the lower quartile of eighth grade.

b)

IQR is calculated as the difference of the Upper quartile and the lower quartile

i.e. Q_3-Q_1

so, IQR of seventh grade is:

22-14=8

IQR of seventh grade=8

IQR of eighth grade is:

34-26=8

Hence, IQR of eighth grade=8

c)

The difference of the median of the two data sets is:

30-18=12

Hence, the difference of median is: 12

d)

As the IQR of both the sets is same i.e. 8.

Hence, the number that must be multiplied by IQR so that it is equal to the difference between the medians of the two sets is:

8\times n=12\\\\n=\dfrac{12}{8}\\\\n=\dfrac{3}{2}\\\\n=1.5

Hence, the number is : 1.5

6 0
3 years ago
Need help on the 2 questions ASAP and SHOW WORK PLEASE !!!! 50 points ????
zaharov [31]

Answer:

-4 - 8-=-4

Step-by-step explanation:

4 0
2 years ago
HELP PLEASE! ALSO CAN U EXPLAIN BECAUSE I NEED TO LEARN AAA m ÷ -1/4 = 6
Sveta_85 [38]
The answer is -3/2 lmk if you need an explanation :)
8 0
3 years ago
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