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statuscvo [17]
3 years ago
12

HELP!!!!!!!!!!!!!!!!!!!!!!!

Mathematics
2 answers:
denis-greek [22]3 years ago
7 0
This is what I got I hope it can help you

erastova [34]3 years ago
3 0
.666 Im not sure on this one hoped it helped..
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Water flows at a rate of 8000 cubic inches per minute into a cylindrical tank. The tank has a diameter of 128 inches and a heigh
beks73 [17]

Answer:

The height of the water = 6.2 in. to the nearest tenth

Step-by-step explanation:

∵ The rate of flows of water into the tank = 8000 in.³/min.

∴ The volume of the water in the tank after 10 min. = 8000 × 10 = 80000 in.³

∵ The water take the shape of the tank

∴ The height of the water = volume of water ÷ Area of the base of the tank

∵ The tank is cylinder with diameter 128 in. and height 72 in.

∴ The area of the base of the tank = π(128/2)²

∴ The height of the water = \frac{80000}{\pi(64)^{2}}=6.2169899

∴ The height of the water = 6.2 in. to the nearest tenth

 

5 0
3 years ago
If the product of the integers a, b, and c is 1, then what is the difference between the largest and the smallest possible
stepladder [879]
Since there are no multiples other than 1 and -1 that could multiply in any way to equal 1, those are the only numbers you can really work with

it is a possibility that a, b, and c could equal 1 but then it would go wrong when comes time to subtract since all numbers are equal and cannot subtract largest from smallest.

a logical approach would be to try -1, -1, and 1 since -1 * -1 = 1 and then 1* 1 =1

we can make a= -1 , b= -1, and c= 1
 (we need b to equal -1 so that we get an answer of -1 opposed to if we made a=-1 and c=-1, all outcomes would equal 1)
-1²=1
-1³=-1
1⁴= 1
since 1 is the largest possible outcome and -1 is the lowest possible outcome you should subtract the two

1-(-1) = 1+1 = 2

The answer should be D: 2
 
hoped this helped at all!
5 0
3 years ago
Please help me find the area for this hexagon (please show work to) ,:)
kvasek [131]

Check the picture below.

so the area of the hexagon is really just the area of two isosceles trapezoids.

\textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} h=height\\ a,b=\stackrel{parallel~sides}{bases}\\[-0.5em] \hrulefill\\ a=2\\ b=4\\ h=2 \end{cases}\implies \begin{array}{llll} A=\cfrac{2(2+4)}{2}\implies A=6 \\\\\\ \stackrel{\textit{twice that much}}{2A = 12} \end{array}

4 0
2 years ago
Find the 11th term of the following geometric sequence.<br><br> 1,5, 25, 125, ...
salantis [7]

Answer:

9,765,625

Step-by-step explanation:

7 0
3 years ago
What are ALL the solutions for 4-9x ≤40
ivolga24 [154]

Answer:

all work is shown and pictured

5 0
3 years ago
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