Answer:
18
Step-by-step explanation: 24/4=6 so if you multiply one by six you must multiply the other by six to make sure they're to the same scale 3*6=18
Answer:
Given : EFGH is a parallelogram.
Prove: EG bisects HF and HF bisects EG.
Since, a parallelogram has two pairs of congruent and parallel sides.
Therefore, In parallelogram EFGH,
EF≅GH and EH≅FG
Also, EF║GH and EH║FG
Since,In triangles EKF and GKH,
EF≅HG
Since, EF║HG
⇒∠FEK ≅ ∠HGK and ∠EFK ≅ ∠ GHK ( When two parallel lines are cut by a transversal alternative interior angles are congruent )
⇒ Δ EKF ≅ Δ GKH ( ASA congruence postulate )
⇒ EK ≅ GK and FK ≅ HK ( CPCTC)
⇒ EG bisects HF and HF bisects EG ( Definition of bisector)
Hence proved.
Answer:
3,315 is the answer
Step-by-step explanation:
1) Just divide
9945 ÷ 3 = 3,315
Not hard
But here my answer!
2000 = x * y
y = 2000 / x
c = 0.3 * (2y + x) + 0.5x = 0.6y + 0.8x = 0.6 * 2000 / x + 0.8x = 1200/x + 0.8x