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nadezda [96]
3 years ago
5

Two triangles have the same heights. One triangle has a base length that is twice the base length of the other triangle. Are the

base lengths and the areas of the two triangles proportional?
Mathematics
1 answer:
djyliett [7]3 years ago
3 0

Answer:

Yes

Step-by-step explanation:

The formula for area of a triangle is A = (1/2)bh,

For the first triangle we can leave it in general terms, so it's area is

A = (1/2)bh, depending on what b and h are, but it doesn't matter here...

The second triangle has base that is twice the other triangles base.  Bases being multiples of each other is the definition of being proportional so the bases are proportional, an the area of the second triangle is

A = (1/2)(2b)h,   which simplifies to

   A = bh

Comparing the 2 areas, you can see that one has a multiplier of (1/2), so their areas are proportional

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PQRS is a square. find the value of x and y.
Ivan

Answer:

x = 7

y = 3/2 or 1.5 (IF THE ANGLE IS 30 BY THE RATIOS OF A RIGHT TRIANGLE.)

hope it's right

Step-by-step explanation:

FOR X:

Let's solve your equation step-by-step.

4x+3=31

Step 1: Subtract 3 from both sides.

4x+3−3=31−3

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Step 2: Divide both sides by 4.

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Step 2: Subtract 21 from both sides.

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