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3 years ago

A motorist travelled 300 km

Mathematics

1 answer:

stealth61 [152]3 years ago

7 0

Answer:

Step-by-step explanation:

Total distance /total time=total speed

600÷60=10hrs

300÷75=4hrs

I0-4=6

V=300÷6=50km/h

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If I have an equation in which x = pounds, and y = total cost, can I substitute quarts into the equation

Colt1911 [192]

Answer:

Yes, you can

Step-by-step explanation:

As a point of reference, assume the equation is:

$y = 5x$

Where

$y = total\ cost$

and

$x = pounds$

In standard unit of conversion:

$1\ pound = 0.4793\ quart$

So:

$x\ pounds = 0.4793x\ quart$

Substitute 0.4793x for x in $y = 5x$

$y = 5 * 0.4793x$

$y = 2.3965x$

The above equation is the equivalent of $y = 5x$ in quarts

<em>So, irrespective of what the equation is, you can always substitute quarts into the equation.</em>

8 0

3 years ago

Solve: 21 = -10m - 3

Pepsi [2]

Answer:

21 = -10m - 3

Add 3 to both sides:

24 = -10m

Divide by -10 on both sides:

-2.4 = m

5 0

3 years ago

Read 2 more answers

3) A toy company is packaging its toys to be shipped. Each toy is placed

Vesnalui [34]

Answer:

560 boxes

Step-by-step explanation:

.25 * 1.75 * 2.5 = 1.09375

1/8 ^3 = 0.001953125

1.09375/0.001953125 = 560

6 0

3 years ago

What’s the answer to this

pantera1 [17]

Answer:

Step-by-step explanation:

Given f(x) the f(x) + c represents a vertical translation of f(x)

• If c > 0 then a shift up of c units

• If c < 0 then a shift down of c units

Here c = - 6, thus a shift down, thus

g(x) = x² - 6 → A

4 0

3 years ago

A water tank has a diameter of 15 ft and is 22 ft high. a. What is the volume of the tank in ft?? b. In m?? c. In cm?

rodikova [14]

Answer:

a) $V = 3887.72 ft^{3}$

b) $V = 104.97 m^{3}$

c) $V = 104,968,468.538 cm^{3}$

Step-by-step explanation:

A tank has the format of a cylinder.

The volume of the cylinder is given by:

$V = \pi r^{2}h$

In which r is the radius and h is the heigth.

The problem states that the diameter is measured to be 15.00 ft. The radius is half the diameter. So, for this tank

$r = \frac{15}{2} = 7.50$ ft

The height of the tank is 22 ft, so $h = 22$ .

a) Volume of the tank in $ft^{3}$ :

$V = \pi r^{2}h$

$V = pi*(7.5)^2*22$

$V = 3887.72 ft^{3}$

b) Volume of the tank in $m^{3}$ :

We must convert both the radius and the height to m.

Each feet has 0.30 m, so:

Radius:

1 feet - 0.30m

7.5 feet - r m

$r = 7.5*0.30$

$r = 2.25m$

Height

1 feet - 0.30m

22f - h m

$h = 22*0.30$

$r = 6.60m$

The volume is:

$V = \pi r^{2}h$

$V = pi*(2.25)^2*6.60$

$V = 104.97 m^{3}$

c) Volume of the tank in $cm^{3}$ :

Each m has 100 cm.

So $r = 2.25m = 225cm$

$h = 6.60m = 660cm$

The volume is:

$V = \pi r^{2}h$

$V = pi*(225)^2*660$

$V = 104,968,468.538 cm^{3}$

7 0

4 years ago