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nata0808 [166]
4 years ago
10

A motorist travelled 300 km

Mathematics
1 answer:
stealth61 [152]4 years ago
7 0

Answer:

Step-by-step explanation:

Total distance /total time=total speed

600÷60=10hrs

300÷75=4hrs

I0-4=6

V=300÷6=50km/h

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Which of the following angle measures are possible for a triangle to be classified as scalene? Select all that apply.
RUDIKE [14]

The angle measures that are possible for a triangle to be classified as scalene are:

  • 7∘,160∘,13∘
  • 48∘,71∘,61∘
  • 15∘,52∘,113∘

<h3>What is scalene triangle?</h3>

A scalene triangle  can be described as a  triangle  which consist three sides and all the three sides are of  different lengths, having  all three angles  with different measures.

It should be noted that  the sum of all the interior angles is  equal to 180 degrees.

In conclusion, scalene triangle serves as the  triangle having all three sides  to be in a  different lengths,  and the  three angles  have different measures.

Learn more about scalene triangle at:

brainly.com/question/16589630

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7 0
2 years ago
The park plans to hire 20 percent more than the minimum number of ticket sellers needed in order to account for sickness, vacati
Ira Lisetskai [31]
The park plans to hire 20 percent more than the minimum number of ticket sellers needed in order to account for sickness, vacation, and lunch breaks. How many ticket sellers should the park hire? Explain.
8 0
2 years ago
Solve this equation for d.
Alborosie

Answer:

d = 12

Step-by-step explanation:

d- 6 = 6

Add 6 to each side

d- 6+6 = 6+6

d = 12

7 0
3 years ago
Read 2 more answers
If r = 3.2, what is the area of the shaded region? Round your answer to the nearest hundredth. Use your calculator's value of π.
Lunna [17]

Answer:

99.38

Step-by-step explanation:

the area of all the circles by using the formula A=ℼr2 then filling in r with 3.2 A=ℼ3.22=32.2

Knowing that one circle is 32.2 4 circles would have an area of 128.8

Two circles have a combined length and height of 12.8 because the circumference of one circle is 6.4 so two circles reach the sides of the square. So all the sides of the square are 12.8. So finding the area of the square knowing what the sides are, so the area is a=163.84. To find the shaded area you subtract the volume of the square to volume of all 4 circles which is 163.84-128.8 which equals 35.04. Then you find the volume of the semi circle which is 64.34. Then the combination of both shaded regions is 99.38

8 0
3 years ago
If f(x) = x3 – x2 – 3, which of the following is equal to g(x) = f(2 – x)?
Andru [333]

Answer:

-x^3+5x^2-8x+1, which is choice A

======================================

Work Shown:

f(x) = x^3 - x^2 - 3

f(x) = (x)^3 - (x)^2 - 3

f(2-x) = (2-x)^3 - (2-x)^2 - 3 ................ see note 1 (below)

f(2-x) = (2-x)(2-x)^2 - (2-x)^2 - 3 ........... see note 2

f(2-x) = (2-x)(4-4x+x^2) - (4-4x+x^2) - 3 ..... see note 3

f(2-x) = -x^3+6x^2-12x+8 - (4-4x+x^2) - 3 ..... see note 4

f(2-x) = -x^3+6x^2-12x+8 - 4+4x-x^2 - 3 ....... see note 5

f(2-x) = -x^3+5x^2-8x+1

----------

note1: I replaced every copy of x with 2-x. Be careful to use parenthesis so that you go from x^3 to (2-x)^3, same for the x^2 term as well.

note2: The (2-x)^3 is like y^3 with y = 2-x. We can break up y^3 into y*y^2, so that means (2-x)^3 = (2-x)(2-x)^2

note3: (2-x)^2 expands out into 4-4x+x^2 as shown in figure 1 (attached image below). I used the box method for this and for note 4 as well. Each inner box or cell is the result of multiplying the outside terms. Example: in row1, column1 we have 2 times 2 = 4. You could use the FOIL rule or distribution property, but the box method is ideal so you don't lose track of terms.

note4: (2-x)(4-4x+x^2) turns into -x^3+6x^2-12x+8 when expanding everything out. See figure 2 (attached image below). Same story as note 3, but it's a bit more complicated.

note5: distribute the negative through to ALL the terms inside the parenthesis of (4-4x+x^2) to end up with -4+4x-x^2


4 0
4 years ago
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