Help me with 5 please

Help?. . What is the equation of the function y=5/x translated 4 units to the left and 3 units up?. . I don't even know where to

Dahasolnce [82]

Y = 5/x
If you want to shift the function 4 units left, you can add 4 to the x-value in the parent function:
y = 5 / ( x + 4 )
After that, you can add 3 to your function to shift it up 3 units.
y = 5 /( x + 4 ) + 3 ( the final equation )

4 0

3 years ago

6xy(1/2x^2--1/3xy+1/6y^2)

Illusion [34]

Place the indicated product in the proper location on the grid.

3x^3y - 2x^2y^2 + xy^3

hope THIS helps even more.

6 0

3 years ago

Find the midpoint of the segment with the given endpoints.

Ksju [112]

The mid-point for given endpoints is (4,3)

Step-by-step explanation:

a mid-point is the point on a line segment that divides it into two equal portions.

If (x1,y1) and (x2,y2) are the coordinates of vertices of a line segment, then mid-point is given by:

$M = (\frac{x_1+x_2}{2}, \frac{y_1+y_2}{2})$

given

(x1,y1) = (9,9)

(x2,y2) = (-1,-3)

$M = (\frac{9-1}{2}, \frac{9-3}{2})\\\\=(\frac{8}{2}, \frac{6}{2})\\\\=(4,3)$

The mid-point for given endpoints is (4,3)

Keywords: Coordinate Geometry, Mid-point

Learn more about coordinate geometry at:

#LearnwithBrainly

5 0

3 years ago

A union of restaurant and foodservice workers would like to estimate the mean hourly wage, μ, of foodservice workers in the U.S.

pav-90 [236]

Answer:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

Step-by-step explanation:

Assuming this complete question: A union of restaurant and foodservice workers would like to estimate the mean hourly wage, , of foodservice workers in the U.S. The union will choose a random sample of wages and then estimate using the mean of the sample. What is the minimum sample size needed in order for the union to be 95% confident that its estimate is within $0.35 of ? Suppose that the standard deviation of wages of foodservice workers in the U.S. is about $2.15 .

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=2.25$ represent the population standard deviation

n represent the sample size

Solution to the problem

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ The margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{s}{\sqrt{n}}$ (a)

And on this case we have that ME =0.35 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 95% of confidence interval now can be founded using the normal distribution. And in excel we can use this formla to find it:"=-NORM.INV(0.025;0;1)", and we got $z_{\alpha/2}=1.960$ , replacing into formula (b) we got:

$n=(\frac{1.960(2.25)}{0.35})^2 =158.76 \approx 159$

So the answer for this case would be n=159 rounded up to the nearest integer

3 0

3 years ago

|x + 1| + 4 ≤ 2

irga5000 [103]

Answer:

no solution

Step-by-step explanation:

8 0

3 years ago