Answer:
<em>figure</em><em> </em><em>of</em><em> </em><em>cuboid</em>
<em>volume</em><em> </em><em>of</em><em> </em><em>cuboid</em><em>=</em><em>l×</em><em>b</em><em>×</em><em>h</em>
Step-by-step explanation:
(10×3×4)in cube=120incube
The formula for illuminance is given by
E = I / d^2
This formula only holds true for one-dimensional illuminance
The problem asks for the illuminance across the floor. We need to use two variables, x and y.
From Pythagorean Theorem
d^2 = x^2 + y^2
and from Trigonometry
x = d cos t
y = d sin t
The function for the illuminance can be represented by the composite function
E = I cos² t / x²
and
E = I sin² t / y²
The boundary of these functions is:
<span>0 < t < 8
So, the value of t must be in radians and not in degrees</span>
I believe it should be the second one down. That one has the lowest residual after the longest period of time, which in this case is the number of days. I hope that helps!
the answer should be 780π
<span>(-2.678) + 4.5 + (-0.68)= 1.142
since .1 is in the tenth place and 42 isnt greater than 50, the answer would be 1.1. </span>