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yuradex [85]
3 years ago
14

QUESTION 3

Mathematics
1 answer:
eduard3 years ago
3 0

Athe answer is -2  because it is behind the 0 and will be negative and it is two lines away from the 0 so the answer is -2

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I believe the answer would be B, good luck 
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Step-by-step explanation:

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Mason plays a game by flipping two fair coins.He wins the game if both coins land facing heads up. If Mason plays 200 times, how
blagie [28]

Answer:

Therefore Mason would be expected to win 50 times.

Step-by-step explanation:

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7 0
4 years ago
D.sqrt(2+x^/2)<br> Solve this question please
lidiya [134]

Answer:

Option a.

Step-by-step explanation:

By looking at the options, we can assume that the function y(x) is something like:

y = \sqrt{4 + a*x^2}

y' = (1/2)*\frac{1}{\sqrt{4 + a*x^2} }*(2*a*x) = \frac{a*x}{\sqrt{4 + a*x^2} }

such that, y(0) = √4 = 2, as expected.

Now, we want to have:

y' = \frac{x*y}{2 + x^2}

replacing y' and y we get:

\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}

Now we can try to solve this for "a".

\frac{a*x}{\sqrt{4 + a*x^2} } = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}

If we multiply both sides by y(x), we get:

\frac{a*x}{\sqrt{4 + a*x^2} }*\sqrt{4 + a*x^2} = \frac{x*\sqrt{4 + a*x^2} }{2 + x^2}*\sqrt{4 + a*x^2}

a*x = \frac{x*(4 + a*x^2)}{2 + x^2}

We can remove the x factor in both numerators if we divide both sides by x, so we get:

a = \frac{4 + a*x^2}{2 + x^2}

Now we just need to isolate "a"

a*(2 + x^2) = 4 + a*x^2

2*a + a*x^2 = 4 + a*x^2

Now we can subtract a*x^2 in both sides to get:

2*a = 4\\a = 4/2 = 2

Then the solution is:

y = \sqrt{4 + 2*x^2}

The correct option is option a.

7 0
3 years ago
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