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Irina18 [472]
3 years ago
12

What is an equation of the line that passes through 7,3 and a slope of 4/7

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
5 0

Answer:

y=(4/7)x-1


Step-by-step explanation:

y=mx+b

3=(4/7)(7)+b

3=4+b

b=-1

y=(4/7)x-1



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<img src="https://tex.z-dn.net/?f=5%5E%7B-3%7D" id="TexFormula1" title="5^{-3}" alt="5^{-3}" align="absmiddle" class="latex-form
AveGali [126]

Answer:

the equivalent equation of

5^{-3}=\frac{1}{5^{3}}=\frac{1}{125}

5 0
2 years ago
martin is ordering dvds online. each dvd is priced at $8.50. the wedsite also charges a flat fee of $5.00 for shipping and handl
Anon25 [30]
Y=8.50x+5.00
56=y
-56=8.50x+5.00

56=8.50x+5.00
-5.00         -5.00
51=8.50x
÷8.5 ÷8.5

6=x  <u>HE CAN BUY 6 DVDS</u>
7 0
3 years ago
How do I write an equation in standard form?
Aleks04 [339]
Do you mean scientific notation
5 0
2 years ago
Read 2 more answers
HELPPP
Bingel [31]

I'm not sure if it only wants you to find Equation 1 or go further and solve:

x = the number of 5c coins

y = the number of 10c coins

Equation 1: the total number of coins is 65

x + y = 65

total value of $3.80

0.05x + 0.1y = 3.8

<u>Simultaneous Equations</u>

Make one coefficient the same

10 * (0.05x + 0.1y = 3.80 = 0.5x + y = 38

x + y = 65

0.5x + y = 38

Subtract the equations

(x + y) - (0.5x + y)= 65 - 38

(x - 0.5x) + (y - y) = 65 - 38

0.5x = 27

x = 54

Substitute it into the original equation to find y.

x + y = 65

54 + y = 56

y = 65 - 54 = 11

Substitute it into the other equation to check it's right.

0.05x + 0.1y = 3.8

0.05(54) + 0.1(65) = 3.8

x = 54 5c coins

y = 11 10c coins

8 0
3 years ago
1/4 x 2/5 x 3/6 x 4/7 x 5/8 x 6/9 x 7/n=?
postnew [5]

Answer:

c. \frac{1}{12n} = {[12n]}^{-1}

Step-by-step explanation:

[\frac{1}{4}][\frac{2}{5}][\frac{1}{2}][\frac{4}{7}][\frac{5}{8}][\frac{2}{3}][\frac{7}{n}] = \frac{560}{6720n} = [12n]^{-1} = \frac{1}{12n}

\frac{2}{3} = \frac{6}{9}\\ \\ \frac{1}{2} = \frac{3}{6}

* To make this simpler, reduce these two fractions in lowest terms.

I am joyous to assist you anytime.

8 0
3 years ago
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