Answer:
Step-by-step explanation:
To prove Δ ABC similar to ΔDBE we can consider
Segments AC and DE are parallel.
⇒ DE intersects AB and BC in same ratio.
AB is a transversal line passing AC and DE.
⇒∠BAC=∠BDE [corresponding angles]
Angle B is congruent to itself due to the reflexive property.
All of them are telling a relation of parts of ΔABC to ΔDBE.
The only option which is not used to prove that ΔABC is similar to ΔDBE is the first option ,"The sum of angles A and B are supplementary to angle C".
Answer:
it can't form isosceles triangle cause any two sides of the triangle are not equal ,it can't form equalateral triangle cause 3 sides of the triangle are not equal and neither right angle triangle so triangle can't be formed
Answer: there no question
Step-by-step explanation:
Answer: t = -93
Step-by-step explanation:
64= -8(t+85)
64= -8t - 680
744= -8t
93= -t
93= t