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DanielleElmas [232]
3 years ago
8

After decreasiag by 8% during the first year, the value of an investment then increased by $450 during the second year. which eq

uation shows the relationship between the original investment value (v) and the value (n) after the second year?
A. 0.08(450+v)=n
B. 0.08v+450=n
C. V+0.08v-450=n
D. V-0.08v+450=n
Mathematics
1 answer:
Tasya [4]3 years ago
6 0

Original investment is V

In the first year V decreased by 0.08V to give V - 0.08V

In the second year; V - 0.08V increased by $450 to give V - 0.08V + $450

The value (n) after two years = V - 0.08V + $450

The correct choice is 'D.'

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Consider randomly selecting a single individual and having that person test drive 3 different vehicles. Define events A1, A2, an
zmey [24]

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Urgent
Damm [24]

The result of our calculations about the rate and time are:

  • r=d/t
  • 200000m/hr
  • 200km/hr
  • km/hr

<h3>What is rate?</h3>

Rate can be regarded as the given object with respect to time.

falcon flies= 800,000 meters

t= 4 hours

We were given the  formula as (d = rt)

d= distance

r = rate

t = time

We can make our calculations as:

part a:

r=d/t

part b:

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part c:

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part d:

km/hr

Learn more about rate at:

brainly.com/question/8728504

#SPJ1

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