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BartSMP [9]
2 years ago
8

The minute hand of a clock is 1.4 centimeters long. How far does the tip of the minute hand travel in 40 minutes? (Round your an

swer to two decimal places.)
Mathematics
1 answer:
ozzi2 years ago
3 0

Answer:

2.93cm

Step-by-step explanation:

I have to admit, this stumped me but I got o work and here's what I have for you. Hope this helps. TIP: remember it is the minute hand not any other hand.

For this one you will have to find the circumference of the clock because as the min hand goes round and round, it will act as a <u>radius</u> and it will go in a <u>circular</u> motion.  

Formula will be π<u>2r</u>= 3.l4 * 2 * 1.4cm=8.792cm per every<u> one</u> revolution of the minute hand. Remembering that for the minute hand to revolve round the clock it has to cover 1 hr = 60min. For you to get the total circumference,

you'll have to take 8.792cm but since it is  per every <u>one</u> revolution of the minute hand, multiply it by 40/60min. <u><em>The answer will be 2.93066cm </em></u><u><em>before rounding off</em></u>. After rounding off you will have <u>2.93cm</u>. Quite lengthy but I assure you after practicing you'll have at your fingertips.  

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2 years ago
The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 mil
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Answer:

69.14% probability that the diameter of a selected bearing is greater than 84 millimeters

Step-by-step explanation:

According to the Question,

Given That, The diameters of ball bearings are distributed normally. The mean diameter is 87 millimeters and the standard deviation is 6 millimeters. Find the probability that the diameter of a selected bearing is greater than 84 millimeters.

  • In a set with mean and standard deviation, the Z score of a measure X is given by Z = (X-μ)/σ

we have μ=87 , σ=6 & X=84

  • Find the probability that the diameter of a selected bearing is greater than 84 millimeters

This is 1 subtracted by the p-value of Z when X = 84.

So, Z = (84-87)/6

Z = -3/6

Z = -0.5 has a p-value of 0.30854.

⇒1 - 0.30854 = 0.69146

  • 0.69146 = 69.14% probability that the diameter of a selected bearing is greater than 84 millimeters.

Note- (The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X)

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